1. Let a and b be coefficients such that
Combining the fractions on the right gives
so that
2. a. The given ODE is separable as
Using the result of part (1), integrating both sides gives
Given that y = 1 when x = 1, we find
so the particular solution to the ODE is
We can solve this explicitly for y :
![\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|](https://tex.z-dn.net/?f=%5Cln%7Cy%7C%20%3D%20%5Cln%5Cleft%7C%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%5Cright%7C)
![\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%7D)
2. b. When x = 9, we get
![y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B45%7D%7B21%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B15%7D7%7D%20%5Capprox%20%5Cboxed%7B1.29%7D)
Answer:
Mr Blake's science class
Step-by-step explanation:
The standard deviation is a measure of variation.
It tells us how far each of the data set in the distribution are far from the mean of the distribution.
The average score of students in Mr. Blake's science class was 73 with a standard deviation of 11, while the average score of students in Mrs. Arnold's class was 75 with a standard deviation of 10.
Since 11>10, Mr Blake's science class is more variable than Mrs. Arnold's class.
Answer:
The ratio of flour to sugar is 2:1
Step-by-step explanation:
Let f = weight of a bag of flour
Let s = weight of a bag of sugar
3f+2s = 32
4f = 32
We have 2 equations and 2 unknowns, we can solve
4f=32
Divide by 4
4f/4 = 32/4
f = 8
Each bag of flour weights 8 pounds
Substitute this back into the first equation
3(8) +2s = 32
24+2s = 32
Subtract 24 from each side
24-24 +2s =32-24
2s = 8
Divide by 2
2s/2 = 8/2
s = 4 pounds
Flours weighs 8 pounds and sugar weights 4 pounds
We want the ratio of flour to sugar
Flour: sugar
8:4
We can divide each side by 4
8/4: 4/4
2:1
Answer:
9
Step-by-step explanation:
