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3 years ago

94 POINTS!!! pls help

Mathematics

2 answers:

svp [43]3 years ago

7 0

Answer:

Hey love! x = 6

Step-by-step explanation:

because 13 x 6 = 78

HOPE THIS HELPS!

Alexus [3.1K]3 years ago

7 0

Answer:

x = 6

Work -

13x = 78

divide 13 on both sides to isolate x. 78 divided by 13 gives us 6, and 13/13 =1.

1 times x is x, as you can see, we have isolated x on one side. On the other side, we got 6, so x = 6

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sergeinik [125]

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Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

The Derivative of a Function

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

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3 years ago

The sum of two numbers is 24 and their quotient is 5 what are the two numbers

ELEN [110]

The numbers are "x" and "y";
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solve this problem by substitution method.
(24-y)/y=5
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x=24-y
x=24-4
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Answer: 3sqrt6

Step-by-step explanation:

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2 years ago