Answer:
The probability of a student receiving a C in the course is p=0.3.
Step-by-step explanation:
We have a absolute frequency for each of the grades (A to F), of a total of 300 course tests.
It is assumed that this sample gives a dood estimation of the distribution of the grades. Then, we can estimate the probability of obtaining a C in the course usign the relative frequency for C.
The relative frequency is calculated as the division between the absolute frequency (in this case, 90 for a C grade) and the size of the sample (in this example, 300).
![p_C=\dfrac{X_C}{N}=\dfrac{90}{300}=0.3](https://tex.z-dn.net/?f=p_C%3D%5Cdfrac%7BX_C%7D%7BN%7D%3D%5Cdfrac%7B90%7D%7B300%7D%3D0.3)
Answer:
a=6
Step-by-step explanation:
write the equation as y=mx+b
y=-5/3x+b
solve for b
1=-5/3*-3+b
1-5=b
b=-4
Plug in -14 and solve for x
-14=-5/3x-4
-10=-5/3x
30/5=x
x=6 (x is basically a because a is the x coordinate)
Answer:
A= 90 , b= 12 , c=60,
Step-by-step explanation:
cuz im smart like that
Answer: b=2A/h.
First, multiple both sides of the equation (A=1/2bh) by 2. You should be left with bh=2A.
Divide both sides of the equation by h. You should be left with b=2A/h.
Hope that helped!