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Degger [83]
3 years ago
9

The perimeter of a rectangular field is 278 m. If the width of the field is 61 m, what is its length?

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

length is 78

Step-by-step explanation:

Perimeter of rectangle is P = 2 (l +w)

278 = 2(l + 61)

l = 78

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WILL GIVE BRAINLIESt:
Andreyy89

Answer:

180

Step-by-step explanation:

Area of troiangle=180

A+B+C=180

22+90+B=90

112+B=180

B=180-112

B=68

perimeter=A+B+C

22+90+68=180

3 0
2 years ago
Read 2 more answers
Draw a number line -5 through 5 and mark 2x<6
inna [77]

Answer:

x < 3

Step-by-step explanation:

Before number line can be drawn, there is need to find the value of x in the inequality given. Thus,

2x < 6

Divide both sides by 2

\frac{2x}{2}  <  \frac{6}{2}

x < 3

The number line is indicated in the attached picture.

8 0
3 years ago
I need help with this question!!!!
Genrish500 [490]

Answer: The answer is A over B if you know what im sayin

Step-by-step explanation:

You take A and B and put the A over the B.

7 0
2 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
2 years ago
Ik this is rlly easy im just to lazy to do it
True [87]
The answer 12/72 because you multiply
4 0
3 years ago
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