Answer:
1) False
As the frequency can be defined as the number of times wave formed per unit time or in other words the numbers of a combination of a crest and trough forms. So the frequncy of a sound wave depends upon the source producing sounds
2)False
Diffraction is the process in which a light wave bends when they pass through a specified medium such as water.
3)True
hope it helps
Answer:
The number of turns in the secondary coil is 4145 turns
Explanation:
Given;
the induced emf on the primary coil,
= 95 V
the induced emf on the secondary coil,
= 875 V
the number of turns in the primary coil,
= 450 turns
the number of turns in the secondary coil,
= ?
The number of turns in the secondary coil is calculated as;


Therefore, the number of turns in the secondary coil is 4145 turns.
This is how you calculate his speed, for the 100metres. That is, the average speed for the entire distance, including the start from intertia until the race end where the athlete is decelerating. Multiply the time by 10, and divide 3600 by that figure. i.e. 10 by10 equals 100. Divide 3600 by 100 and you get 36 which is the speed figure you requested.
A female athlete ran 200 metres a few years ago and in the middle section of the race covered 100 metres in that race in a time under 10 seconds. That is, she ran a sub 10second 100metres from a flying start. This great athlete from Slovenia, also ran a 100 metre race (from a stationary start) in a time under 11 seconds, when she was 48 years of age. Her name is Merlene Ottey.
Answer:
V = 4.859[m^3]
Explanation:
In order to solve this problem, we must find the mass of the refrigerant, as there are no leaks or leaks of refrigerant, we can conclude that the mass is conserved throughout the process.
For saturation conditions, we can find the specific volume, in the attached table of saturation values for pressure of 0.9 [MPa] we can see the specific volume.
![v=0.0008580[m^3/kg]](https://tex.z-dn.net/?f=v%3D0.0008580%5Bm%5E3%2Fkg%5D)
with the volume of 0.03 [m^3], we can find the mass.
![m = \frac{V}{v} \\m= \frac{0.03}{0.0008580} \\m=34.96[kg]](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7BV%7D%7Bv%7D%20%5C%5Cm%3D%20%5Cfrac%7B0.03%7D%7B0.0008580%7D%20%5C%5Cm%3D34.96%5Bkg%5D)
Now using the superheat tables for the 134a we can find the specific volume
Since it is difficult to find the specific volume value for a pressure of 280 [kPa] & T = 208[C], with over-heated refrigerant. We go to the diagram of this refrigerant to see if the condition is over heating exists to these conditions.
In the second image attached we can see that, there is the superheating condition, highlighted at the end of the red line. And that the specific volume is approximately equal to 0.15[ m^3/kg].
Therefore we can take a normal table of coolant overheating 134a to P= 0.28[ MPa] and make an extrapolation.
the extrapolation will be with the following values:
130 = 0.11512
140 = 0.11818
208 = 0.139 [m^3/kg]
![V = m*v \\where:\\m = 34.96[kg]\\v = 0.139[m^3/kg]\\V = 34.96*0.139\\V = 4.859[m^3]](https://tex.z-dn.net/?f=V%20%3D%20m%2Av%20%5C%5Cwhere%3A%5C%5Cm%20%3D%2034.96%5Bkg%5D%5C%5Cv%20%3D%200.139%5Bm%5E3%2Fkg%5D%5C%5CV%20%3D%2034.96%2A0.139%5C%5CV%20%3D%204.859%5Bm%5E3%5D)
Answer:
You go to their comment and click Brainliest.
Explanation: