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ICE Princess25 [194]
3 years ago
10

a transformer changes 95 v acorss the primary to 875 V acorss the secondary. If the primmary coil has 450 turns how many turns d

oes the seconday have g
Physics
1 answer:
natita [175]3 years ago
8 0

Answer:

The number of turns in the secondary coil is 4145 turns

Explanation:

Given;

the induced emf on the primary coil, E_p = 95 V

the induced emf on the secondary coil, E_s = 875 V

the number of turns in the primary coil, N_p = 450 turns

the number of turns in the secondary coil, N_s = ?

The number of turns in the secondary coil is calculated as;

\frac{N_p}{N_s} = \frac{E_p}{E_s}

N_s = \frac{N_pE_s}{E_p} \\\\N_s = \frac{450*875}{95} \\\\N_s = 4145 \ turns

Therefore, the number of turns in the secondary coil is 4145 turns.

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Answer:

<h3>14.97m/s</h3>

Explanation:

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Answer:

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\frac{N}{N_{o}} = (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

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A spherical capacitor is formed from two concentric sphericalconducting shells separated by vacuum. The inner sphere has radius1
zubka84 [21]

Explanation:

(1).  Formula to calculate the potential difference is as follows.

       \Delta V = -\int E dr

                  = -\int \frac{kq}{r^{2}} dr

                 = \frac{kq}{r_{f}} - \frac{kq}{r_{i}}

                 = \frac{kq(r_{f} - r_{i})}{r_{f}r_{i}}

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Therefore, magnitude of the potential difference between the two spheres is 38.7 volts.

(2).  Now, formula to calculate the energy stored in the capacitor is as follows.

           E = \frac{1}{2}QV

              = \frac{1}{2} \times 3.30 \times 10^{-9} \times 3.87 V

              = 6.39 \times 10^{-8} J

Thus, the electric-field energy stored in the capacitor is 6.39 \times 10^{-8} J.

7 0
3 years ago
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