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ICE Princess25 [194]

3 years ago

10

a transformer changes 95 v acorss the primary to 875 V acorss the secondary. If the primmary coil has 450 turns how many turns d

oes the seconday have g

1 answer:

natita [175]3 years ago

8 0

Answer:

The number of turns in the secondary coil is 4145 turns

Explanation:

Given;

the induced emf on the primary coil, $E_p$ = 95 V

the induced emf on the secondary coil, $E_s$ = 875 V

the number of turns in the primary coil, $N_p$ = 450 turns

the number of turns in the secondary coil, $N_s$ = ?

The number of turns in the secondary coil is calculated as;

$\frac{N_p}{N_s} = \frac{E_p}{E_s}$

$N_s = \frac{N_pE_s}{E_p} \\\\N_s = \frac{450*875}{95} \\\\N_s = 4145 \ turns$

Therefore, the number of turns in the secondary coil is 4145 turns.

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${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\$

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${\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\$

$\:\:\:\:\bullet\:\:\:\sf{Left \: Penetration \: length \: before \: it \: comes \: to \: rest \:( s_{2} )}$

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$\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} + 2as }$

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$\dashrightarrow\:\: \sf{ a = \dfrac{ - 25 {v}^{2} }{2}\:m/s^{2} ......(1) }$

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$\dashrightarrow\:\: \sf{ - {v}^{2} = - 25 {v}^{2} \times s }$

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$\dashrightarrow\:\: \sf{ s_{2} = 0.04 - 0.03 }$

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