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Andreas93 [3]
4 years ago
15

What physical property makes wax good for making molds for making sculptures

Chemistry
2 answers:
Scrat [10]4 years ago
8 0
<h2><u><em>It's malleability</em></u> Is what makes wax good for making molds </h2>
dmitriy555 [2]4 years ago
8 0

Answer:

<h2>Malleability.</h2>

Explanation:

Malleability is a physical property that allows the material to deformed without  cracking. Thanks top this property, you can obtain very thins layer of some materials like wax. People often confuse this with ductilibility, but the difference is that the last one are forced to make threads of the material.

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The density of an unknown gas at 98°C and 740 mmHg is 2.50 g/L. What is the molar mass of the gas with work showed?
noname [10]

Answer:

78.2 g/mol  

Step-by-step explanation:

We can use the <em>Ideal Gas Law</em> to solve this problem:

       pV = nRT

Since n = m/M, the equation becomes

      pV = (m/M)RT     Multiply each side by M

   pVM = mRT               Divide each side by pV

        M = (mRT)/(pV)

Data:

ρ = 2.50 g/L

R = 0.082 16 L·atm·K⁻¹mol⁻¹

T =98 °C

p = 740 mmHg

Calculation:

(a)<em> Convert temperature to kelvins </em>

T = (98 + 273.15) = 371.15 K

(b) <em>Convert pressure to atmospheres </em>

p = 740 × 1/760 =0.9737 atm

(c) <em>Calculate the molar mass </em>

Assume V = 1 L.

   Then m = 2.50 g

            M = (2.50 × 0.082 06 × 371.15)/(0.9737 × 1)

                = 76.14/0.9737

                = 78.2 g/mol

3 0
3 years ago
The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3
Oksanka [162]

Answer : The mass of NaN_3 required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = 113 L

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 85^oC=273+85=358K

Putting values in above equation, we get:

1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K

n=3.84mol

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 3 mole of N_2 produced from 2 mole of NaN_3

So, 3.84 moles of N_2 produced from \frac{2}{3}\times 3.84=2.56 moles of NaN_3

Now we have to calculate the mass of NaN_3

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

Molar mass of NaN_3 = 65 g/mole

\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g

Therefore, the mass of NaN_3 required is, 166.4 grams.

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