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3 years ago

CaC2 + 2H2O ⟶ C2H2 + Ca(OH)2 How many moles of water are needed to produce 56.8g C2H2?

Chemistry

1 answer:

pshichka [43]3 years ago

6 0

Amount of moles of water is 4.36 mol

Explanation: M(C2H2) = 2·12.01 + 2·1.008 = 26.036 g/mol

Amount of substance is n= m/M= 56.8 g / 26.036 g/mol= 2.18159 mol

Water is needed 2·2.18 mol = 4.36 mol

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Suppose you are titrating vinegar, which is an acetic acid solution

kotegsom [21]

Answer:

0.373 M

Explanation:

The balanced equation for the reaction is given below:

HC2H3O2 + NaOH —> NaC2H3O2 + H2O

From the balanced equation above, the following were obtained:

Mole ratio of the acid, HC2H3O2 (nA) = 1

Mole ratio of the base, NaOH (nB) = 1

Next, we shall write out the data obtained from the question. This include:

Volume of base, NaOH (Vb) = 32.17 mL

Molarity of base, NaOH (Mb) = 0.116 M

Volume of acid, HC2H3O2 (Va) = 10 mL

Molarity of acid, HC2H3O2 (Ma) =..?

The molarity of the acid solution can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 10 / 0.116 x 32.17 = 1

Cross multiply

Ma x 10 = 0.116 x 32.17

Divide both side by 10

Ma = (0.116 x 32.17) /10

Ma = 0.373 M

Therefore, the concentration of the acetic acid is 0.373 M.

8 0

3 years ago

On a cool morning (12"C), a balloon is filled with 1.5 L of helium. By mid afternoon, the temperature has soared to 32°C. What i

ddd [48]

Answer:

1.6 L

Explanation:

Using Charle's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = 1.5 L

V₂ = ?

T₁ = 12 °C

T₂ = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (12 + 273.15) K = 285.15 K

T₂ = (32 + 273.15) K = 305.15 K

Using above equation as:

$\frac{1.5}{285.15}=\frac{V_2}{305.15}$

$V_2=\frac{1.5\cdot \:305.15}{285.15}$

New volume = 1.6 L

8 0

3 years ago

Make a plan to partition the mixture of iron chips, water and alcohol.

DanielleElmas [232]

Answer:

water into drop alcohol

Explanation:

alcohol first burn

4 0

3 years ago

Which of the following does not serve as a way to neutralize the charge in a body?

xenn [34]

<u>Answer: </u><em>B. Adding more protons to a positively charged body until the number of protons matches the number of electrons</em>

Option B is the appropriate response

<u>Explanation:</u>

Utilising the equivalent number of inverse charges will kill a charged body.

Adding more protons to a decidedly charged body until the number of protons coordinates the quantity of electrons won't kill the body since protons are emphatically charged particles. Adding more protons to an emphatically charged body would make it all the more decidedly charged.

Enabling free electrons to escape from a contrarily charged body will kill since the more negative body leaves the negative electrons.

3 0

3 years ago

Read 2 more answers

Remember to balance the equations first

Semenov [28]

mol CO₂ = 9.6

mol N₂ = 4.8

mol O₂ = 0.8

mol H₂O = 8

<h3>Further explanation</h3>

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