Answer:
a. operands are evaluated left toright. 7
b. operands are evaluated right toleft. 12
Explanation:
a. operands are evaluated left toright. 7
b. operands are evaluated right toleft. 12
left to right
int fun (int *i) {
*i +=5; we add 5to x making x 8
return4; we return 4 tomain
}
void main ( ) {
int x = 3;
x = x + fun(&x); x starts at 3 in fun it ischanged to 8 but the 3 is already being used the 4 fromfun is added (3+4) to it making it 7
}
right toleft x starts at 3 in fun x gets changed to 8 and fun is returned as 4so we have 4 + 8 = 12
Paraphrasing
left to right it's is 3 + 4 =7 original value of x is used
right to left it is 4 + 8 =12 x is used as it was changed by fun, since fun was alreadyexecuted
B (locate web pages related to specific subject); can search to find books on certain topics
A person responsible for running a business, organization, etc.
Using the knowledge in computational language in LC-3 Assembly it is possible to write a code that replaces the value in R0 with its absolute value
<h3>Writting the code </h3>
.ORIG x0200
START
AND R0, R0, #0 ; copy R0 to itself to set the condition codes based on R0;
; i.e performing addition operation with Zero option to set the flags
BRzp DONE ; if R0 is NON-NEGATIVE, skip the negation (already correct);
; Branch to DONE if number is poistive
NOT R0, R0 ; R0 is negative, so negate it i.e taking 2's complement
ADD R0, R0, #1 ; R0 = -R0 is performed successfully
DONE BR START
.END
See more about LC-3 Assembly at brainly.com/question/12978370
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Answer:
ADGH AVFH VVBLA FDHLAVRGLBHSRGLHFSgh HGK g gH G avoshhbv so bhsf vhbfsb gfsb gb gh g hhow gw
Explanation:
eehhfhsghOhrrbfghedhchggfgsbbfbhdhfhehyfnfnhhsh
