1,119.6 in. the answer is c my diddle.
Find the area of the hexagon which is 259.81
Find the area of the squares which is (6)100
Find the area of the triangles which was (6)43.3
259.81 + 600 + 259.8
519.6 + 600 = 1119.6
The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
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Answer:
2) reflexive property
3) given
4) substitution postulate
5) substitution postulate
6) addition postulate
7) partition postulate
8) equal length line segments are congruent
9) SSS theorem
Step-by-step explanation:
Answer:
2 : 3
Step-by-step explanation:
Given:
The two cylinders are similar. So, their corresponding dimensions must be in proportion.
Therefore, the similarity ratio of the smaller to the larger similar cylinders is 2 : 3.
Answer:
109
Step-by-step explanation:
