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Xelga [282]
3 years ago
5

Evaluate -2 x 2y , if x = -3 and y = -1. -12 -18 18 12

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

-559872

Without adding in the additonal Numbers

-4xy

Step-by-step explanation:

<u><em>Im most likely way off so please, i am Not going to guarantee that this answer is correct </em></u>

<u><em>(This is the first time ive been unsure of my Answer so please take my warning into consideration) </em></u>

<u></u>

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Me need help in math
xxMikexx [17]
The answer is d because 42/45 as a percentage is 93
7 0
3 years ago
Despeja g.<br> -3+5+6g=11-3g
Len [333]

Answer: The value of g is 1

Step-by-step explanation:

To solve for g in the algebraic expression below: collect like terms

-3+5+6g=11-3g

2 + 6g = 11 - 3g

Let the whole algebraic expression equal zero by moving 11 -3g to left hand side while the minus sign becomes plus sign '+' since it crossed the equality sign '=')

Thus, 2 + 6g - 11 + 3g = 0

collect like terms again

2 - 11 + 6g + 3g = 0

-9 + 9g = 0

-9 = -9g

Divide both sides by -9

-9/-9 = -9g/-9

1 = g

Thus, the value of g is 1

5 0
3 years ago
Use the shell method to find the volume of the solid generated by revolving the regions bounded by the curves and lines about th
RSB [31]

Answer:

The volume of the solid is:

\displaystyle\frac{19\pi}{6}

Step-by-step explanation:

See the graph of the region attached.

To find the intersection between the line and the parabola we set the equation equal to each other, and solve that quadratic equation by factorization:

x^2=9-8x\\x^2+8x-9=0\\(x+9)(x-1)=0\\x=-9,x=1

Since the region is the one for x\ge 0 then the intersection we are interested on is x=1 as it can also be seen in the graph.

Then we set the integral using shell method for revolving about the y-axis:

\displaystyle\int_a^b 2\pi\,x\,h(x)\,dx

Where h(x) is the height of the shell which here is the distance between the parabola and the line, so 8x-9-x^2 (since the line is on the top we subtract from it the parabola)

Then the integral becomes:

\displaystyle\int_0^1 2\pi\,x\,(8x-9-x^2)\,dx

Notice the limits of the integral are the x-axis (x=0) and the intersection of the parabola and the line that we found before (x=1)

Now, solving the integral:

Start by factoring the 2\pi and distributing the x:

=\displaystyle2\pi \int_0^19x-8x^2-x^3dx

Then use the basic rule to integrate:

=\displaystyle2\pi \left[\frac{9x^2}{2}-\frac{8x^2}{3}-\frac{x^4}{4}\right|_0^1

Then evaluate the antiderivative in the limits and subtract:

=\displaystyle2\pi\left[\frac{9}{2}-\frac{8}{3}-\frac{1}{4}-0\right]=\frac{19\pi}{6}

So the volume of the solid is \displaystyle\frac{19\pi}{6}

4 0
3 years ago
PLEASE HELP ( I can mark if brainlest, no fake answers please)
Liula [17]

Answer:

$80

Step-by-step explanation:

plug 40 into each equation for x

50+12(40)

simplify

50+480

simplify

530

10+15(40)

simplify

10+600

610

now subtract 530 from 610

610-530

80

7 0
3 years ago
If h(x) = −2x − 10, find h(−4). (1 point) −2 −18 −3 −16
BaLLatris [955]

Use the substitution method

h(x) = −2x −10

h(-4)= -2(-4)-10

Multiply first then do -10

8-10

h(-4)= -2

Answer : h(-4)= -2 : first choice

3 0
3 years ago
Read 2 more answers
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