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fiasKO [112]
3 years ago
13

Plz help ASAP!!!!!it has to be right!!!!!will mark brainiest

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

m∠GKH = m∠JKI  Subtraction Property

Step-by-step explanation:

Given:

Line GI intersects line JH at point K. The proof of ∠GKH ≅ ∠JKI is shown.

To complete the 5th step in the proof.

Solution:

In order to prove ∠GKH ≅ ∠JKI , we need to first show that m∠GKH = m∠JKI .

We can use properties of equality to prove it.

4th Step is as follows :

m\angle GKH+m\angle HKI=m\angle JKI+m\angle HKI

Using subtraction property:

Subtracting both sides by m∠HKI

m\angle GKH+m\angle HKI-m\angle HKI=m\angle JKI+m\angle HKI-m\angle HKI

Thus, we have the 5th step as:

m\angle GKH=m\angle JKI

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1. 1 cup of concentrate would use 7.5 cups of water.

2. 10 cups of concentrate would use 75 cups of water.

Step-by-step explanation:

Because 1/3 cup of concentrate is mixed with 2 1/2 cups of water, to find how much water one cup of concentrate would use, you would have to multiply both 1/3 and 2 1/2 (2.5) by 3. Then, you get 1 cup of concentrate equals 7 1/2 (7.5).

To find the answer to the next question, simply multiply by 10.

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Step-by-step explanation:

The confidence interval for population proportion is given by :-

p\ \pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

Given : Sample size : n=1000

The proportion of people selected consumers who had opportunities to send in a rebate claim form after purchasing a product said they never did so =\dfrac{250}{1000}=0.25

Significance level : 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Now, the 95% confidence Interval for the true proportion of such consumers who never apply for a rebate will be :-

0.25\ \pm (1.96)\sqrt{\dfrac{0.25(1-0.25)}{1000}}\\\\\approx0.25\pm0.0268\\\\=(0.2232,\ 0.2768)

Hence, a confidence Interval for the true proportion of such consumers who never apply for a rebate .

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melisa1 [442]

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<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define expression</u>

√-216

<u>Step 2: Simplify</u>

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  3. Multiply:                   6i√6
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