Which two super powers engaged in the cold war?

Angelo is trying to save up to buy the new iPhone 11. He has $40 in his wallet. He decides to shovel snow off driveways for $30

rewona [7]

The equation that best models this situation would be: y=40+30x

5 0

3 years ago

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x f(x) 2.0 2.8 2.5 1.1 3.0 –0.8 3.5 –1.2 4.0 –0.3 4.5 0.7 For the given table of values for a polynomial function, where must th

GarryVolchara [31]

Below are the choices that can be found from other sources:

A. between 2.0 and 2.5 and between 4.0 and 4.5
B. between 2.5 and 3.0 and between 4.0 and 4.5 
C. between 2.0 and 2.5 and between 3.5 and 4.0 
D. between 2.5 and 3.0 and between 3.5 and 4.0

The answer is B.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

5 0

3 years ago

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Tensile-strength tests were carried out on two different grades of wire rod (Fluidized Bed Patenting of Wire Rods, Wire J., June

Shtirlitz [24]

Answer:

$t=\frac{(123.6-107.6)-(10)}{\sqrt{\frac{2^2}{129}+\frac{1.3^2}{129}}}=28.569$

$p_v =P(t_{256}>28.569) \approx 0$

So with the p value obtained and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10 kg/mm2.

Step-by-step explanation:

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2 +10$

Alternative hypothesis: $\mu_1 >\mu_2 +10$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 \leq 10$

Alternative hypothesis: $\mu_1 -\mu_2>10$

Our notation on this case :

$n_1 =129$ represent the sample size for group AISI 1078

$n_2 =129$ represent the sample size for group AISI 1064

$\bar X_1 =123.6$ represent the sample mean for the group AISI 1078

$\bar X_2 =107.6$ represent the sample mean for the group AISI 1064

$s_1=2.0$ represent the sample standard deviation for group 1 AISI 1078

$s_2=1.3$ represent the sample standard deviation for group AISI 1064

And now we can calculate the statistic:

$t=\frac{(123.6-107.6)-(10)}{\sqrt{\frac{2^2}{129}+\frac{1.3^2}{129}}}=28.569$

Now we can calculate the degrees of freedom given by:

$df=129+129-2=256$

And now we can calculate the p value using the altenative hypothesis:

$p_v =P(t_{256}>28.569) \approx 0$

So with the p value obtained and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10 kg/mm2.

7 0

3 years ago

Hi!!! please help! :)))

romanna [79]

Answer:

1) x

2) x√2

3) x

Step-by-step explanation:

8 0

2 years ago

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Which of the following sets

Ostrovityanka [42]

Answer:

b

Step-by-step explanation:

because the sum of two opposite interior angle is equal to the exterior angle

if one angle is 11 and the other one is 3

then the sum is 14

so the right answer is b

4 0

2 years ago