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makkiz [27]
3 years ago
9

Is 21 3/7 a rational or an irrational number?​

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

Rational

Step-by-step explanation:

This number is rational because it can be expressed as a ratio between two numbers.

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What are the steps for adding and subtracting mixed numbers with unlike denominators
Valentin [98]
Well, there are different ways to do this if you are really familiar with fractions, but "officially" :P

1) convert mixed numbers to improper fractions.

rule:  a b/c = (ac+b)/c

2)  make all fractions have a common denominator...

a/b+c/d

(a/b)(d/d)+(c/d)(b/b)

(ad/bd)+(cb/bd)

3)

The simplify your final answer with greatest common denominator or convert back to mixed number if needed...
5 0
3 years ago
Read 2 more answers
- 7(2-1) = 28<br> The solution is?
Aneli [31]

Answer:

Is there a x somewhere or is that litteraly how the equation is?

If so, -7 multiplied by 2 is -14,

-1 times -7 is 7,

add it together and you get

-7=28,

you could add 7 to both sides or subtract 28 from both sides and you'll get either 0=35 or -35=0

which would make the solution false since both sides are not the same

6 0
4 years ago
Write out the form of the partial fraction decomposition of the function (as in this example). do not determine the numerical va
neonofarm [45]
\frac{x^{4}-2x^{3}+x^{2}+7x-5}{x^{2}-2x+1} = x^{2}+\frac{a}{x-1}+\frac{b}{(x-1)^{2}}
It looks like your first selection (a) is appropriate.
7 0
3 years ago
[21] Please help. What is the volume of the cooler in cubic inches?
GenaCL600 [577]

Answer:

3,724

Step-by-step explanation: Length x width x height

19 x 14 x 14

19 x 14 = 266

266 x 14 = 3,742

hope this helped :)

6 0
3 years ago
20 POINTS
USPshnik [31]

Answer:

a) Only the first one is an identity.

Step-by-step explanation:

1). 8 cos O tan O csc O = 8   simplifies to:

cos O tan O csc O = 1

cos O * (sin O / cos O) * (1 /sin O)

=  cos O sin O / cos O sin O

= 1

So it is identity.

2) 13 sec^2 O/ cos^2 O - tan^2 O / cos^2O

= 13 sec^2 O - tan^2 O / cos^2 O

Now  sec^2 O = 1 + tan^2 O, so we have:

(13( 1 + tan^2 O) - tan^2 O) / cos^2 O

= (12 tan^2 O + 13) / cos^2 O

This is not always = 2 so its not an identity.

4 0
3 years ago
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