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raketka [301]
3 years ago
12

Gracie is shipping a cube shaped box. It measures 14in x 14in x 14in. What is the surface area of the box?

Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0
14× 14 = 196 area of 1 of the squares. on a cube there are 6 squares so multiply 196 by 6

196 × 6 = 1176 sq in
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saul85 [17]
D.(6,3)

because your in put is not the same as any of the other in puts
3 0
3 years ago
Carl deposited $5,142 into a savings account 20 years ago. The account has an interest rate of 3.8% and the balance is currently
Aleksandr [31]
Here is the formula you'll need
Total = Principal * (1 + (rate/n))^n*years
I don't know how to solve that for "n" so we'll use trial and error.

If compounded annually, total = <span> <span> <span> 10,841.24 </span> </span> </span>
If compounded quarterly, total = <span> <span> <span> 10,955.64 </span>
</span></span><span>If compounded monthly, total = </span> <span> <span> <span> 10,981.82 </span> </span> </span>
If compounded daily, total = <span> <span> <span> 10,994.58 </span> </span> </span>
Therefore the answer is "A", daily.

Source:
http://www.1728.org/compint3.htm


<span> </span><span><span> </span> </span>

3 0
3 years ago
A simple random sample of n measurements from a population is a subset of the population selected in a manner such that which of
Ierofanga [76]

Answer:

a) sample of size n from the population has an equal chance of being selected.

b) Every member of the population has an equal chance of being included in the sample.                                            

Step-by-step explanation:

Simple random sampling:

  • It is a type of probabilistic sampling.
  • It is an unbiased representation of population.
  • The probability of selection is equal for every observation.
  • A sample is taken in such a way that each member has an equal probability of being selected.
  • A simple random sample is a subset of a statistical population in which each member of the subset has an equal probability of being chosen.
  • Thus,the correct interpretation is given by,

a) sample of size n from the population has an equal chance of being selected.

b) Every member of the population has an equal chance of being included in the sample.

  • c) The simplest method of selection is used to create a representative sample.

The statement is false.

There is no pattern or technique used for selection. The selection is purely random.

  • d) Each subset of the population has an equal chance of being included in the sample.

The statement is false.

Each object of the population has an equal chance of being included in the sample. and not each subset.

  • e) Every sample of size n from the population has a proportionally weighted chance of being selected.

The given statement is false.

8 0
3 years ago
Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0
3 years ago
Two squares have areas of 4 cm?
timofeeve [1]

Answer:

1/2

Step-by-step explanation:

First square area = 4cm^2, thus the side length is 2cm

Second square area = 16cm^2, thus the side length is 4cm

This gives a ratio of 2/4, simplifying yields 1/2

3 0
2 years ago
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