X+y=62 ; x-y=12 Solve for x in one equation and plug that value into the other equation. ===> x=12+y ; 12+y+y=62 Subtract 12 to both sides (2y=50), then divide by 2 to find y (y=25). Now, plug 25 as y into x=12+y, getting x=37. Your two numbers are 37 and 25.
Answer:
(2, 3 )
Step-by-step explanation:
Given the 2 equations
2x - 3y = - 5 → (1)
5x + 4y = 22 → (2) [ rearranged equation ]
Multiplying (1) by 4 and (2) by 3 and adding will eliminate the term in y
8x - 12y = - 20 → (3)
15x + 12y = 66 → (4)
Add (3) and (4) term by term to eliminate y, that is
23x = 46 ( divide both sides by 23 )
x = 2
Substitute x = 2 in either of the 2 equations and evaluate for y
Substituting into (2)
5)2) + 4y = 22
10 + 4y = 22 ( subtract 10 from both sides )
4y = 12 ( divide both sides by 4 )
y = 3
Solution is (2, 3 )
The answer is 26.7 because you have to add all the total length up.
Answer:
B (second graph from left)
Step-by-step explanation:
The function when x=0 will be 1 since any number to the zero exponent is 1. This means only B and D are options.
Because of the fraction, the values will be smaller and have a gentler slope. B is the solution.
