1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
scoray [572]
3 years ago
8

The outside diameter (od) of a pipe is 4 9/32 inches. The walls are 7/32 inches thick. find the inside diameter.

Mathematics
2 answers:
Ne4ueva [31]3 years ago
8 0
The outside diameter of a peace is 4 9:32 inches
sergij07 [2.7K]3 years ago
4 0

The inside diameter would be the outside diameter minus 2 of the wall thicknesses.

4 9/32 - (2 x 7/32)

Simplify:

4 9/32 - 14/32

Because 14/32 is larger than 9/32 change one of the hole numbers to a fraction: 1 = 32/32

rewrite 4 9/32 as 3 41/32

Now subtract:

3 41/32 - 14/32 = 3 27/32 inside diameter.

You might be interested in
Why is the inequality x≤6 equivalent to the inequality x−5≤6−5
Monica [59]

Two inequalities are equivalent if they have the same set of solutions.

x - 5 ≤ 6 - 5

x - 5 ≤ 1    |add 5 to both sides

x ≤ 6

8 0
3 years ago
Identify the figure below select two names that apply
Ilya [14]
Parallelogram, quadrilateral, rhombus
4 0
3 years ago
Read 2 more answers
What is the equation,
Orlov [11]

The equation, in slope-intercept form, of the line that is perpendicular to the line y- 4 = -(x-6) and passes through the point (-2,-2) is y = x.

<h3 />

<h3>How to represent equation in slope intercept form?</h3>

The equation in slope intercept form is represented as follows;

y = mx + b

where

  • m = slope
  • b = y-intercept

Therefore,

perpendicular lines follows the rule as follows;

m₁m₂ = -1

Therefore,

y - 4 = -(x - 6)

y - 4 = -x + 6

y = -x + 6 + 4

y = -x + 10

Therefore,

-1m₂ = -1

m₂ = 1

Hence, the line passes through (-2, -2).

Therefore,

-2 = 1(-2) + b

b = -2 + 2

b = 0

Therefore, the equation is as follows;

y = x

learn more on equation here: brainly.com/question/18611223

#SPJ1

8 0
2 years ago
Evaluate the expression 7C6
stealth61 [152]
The answer is 7
Hope this helps

3 0
4 years ago
Read 2 more answers
Solve this rational equation ​
tino4ka555 [31]

Answer:

<h2>x = -1</h2>

Step-by-step explanation:

\text{Domain:}\\\\x-4\neq0\ \wedge\ x-2\neq0\ \wedge\ x^2-6x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x^2-4x-2x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x(x-4)-2(x-4)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ (x-4)(x-2)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x-4\neq0\ \wedge\ x-2\neq0\\\\\boxed{D:x\neq4\ \wedge\ x\neq2}

\dfrac{1}{x-4}+\dfrac{x}{x-2}=\dfrac{2}{x^2-6x+8}\\\\\dfrac{1(x-2)}{(x-4)(x-2)}+\dfrac{x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\\\\\dfrac{x-2+x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\iff x-2+x(x-4)=2\\\\x-2+(x)(x)+(x)(-4)=2\\\\x-2+x^2-4x=2\qquad\text{subtract 2 from both sides}\\\\x^2-3x-4=0\\\\x^2-4x+x-4=0\\\\x(x-4)+1(x-4)=0\\\\(x-4)(x+1)=0\iff x-4=0\ \wedge\ x+1=0\\\\x-4=0\qquad\text{add 4 to both sides}\\x=4\notin D\\\\x+1=0\qquad\text{subtract 1 from both sides}\\x=-1\in D

8 0
3 years ago
Other questions:
  • Each lapel on a suit jacket is in the shape of a triangle.the three angles of each triangle measure 47 , 68 and 65. classify the
    11·1 answer
  • A palimage of a natural number is the number which has the same digits but in reverse order. For example, 659 and 956 are palima
    14·1 answer
  • I need help can someone please help me with this ​
    6·2 answers
  • Which fruit has the lowest unit price?
    7·2 answers
  • The population of a town increased from 5,600 to 6,300 people. What was the percent of the increase?
    15·2 answers
  • 20 POINTS
    10·1 answer
  • Mathematic uh coordinate planes ty and brainlist for the first person to answerr it right
    8·1 answer
  • If tanA=1/7 and tanB=1/3 prove that cos2A=sin4B
    14·1 answer
  • 1/6(49/9-14/3)+27/73/5×33​
    9·1 answer
  • 4x+ 3y =2 5x+3y=-2 <br> step by step Elimination
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!