
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

RADIUS = 2
CHORD = 2
RADIUS --> XY , XZ , WX
( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

AREA COVERED BY THE ANGLE IN A SEMI SPHERE


Total Area Of The Semi Sphere:-

Area Under Unshaded Part .
Given a triangle with each side 2 units.
This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian
So AREA :-


Total Area - Area Under Unshaded Part


$80 times 0.25 equals 20
80 minus 20 equals 60 bucks
Answer:
The approximate volume of the sphere= 4187 cubic units
Step-by-step explanation:
<u>Points to remember</u>
Volume of sphere = (4/3)πr³
Where 'r' radius of sphere
<u>To find the volume of sphere</u>
It is given that the radius of the sphere is 10 units. ,
Here radius r = 10 units
Volume = (4/3)πr³
= (4/3) * 3.14 * 10³
= (4/3) * 3140
= 4186.666 ≈ 4187 cubic units
The diagonal line is the hypotenuse of a triangle whose sides are both 50 yds, so you can use Pythagoras (a^2 + b^2 = c^2) to find the answer. 50 × 50 = 2500, and 2500 + 2500 = 5000. Because 5000 is c^2, the answer is D) √5000. I hope this helps!