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Vedmedyk [2.9K]
3 years ago
5

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng

th 2. What is the area of the shaded sector formed by obtuse angle WXY?​

Mathematics
1 answer:
gladu [14]3 years ago
5 0

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

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