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3 years ago

Find the distance between -7/8 and 3/8 on a number line

1 answer:

3 0

The distance is ten because first you minus the -7 to bring you to 0/8 and then you jump over 3 more to give you your distance

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1. Stewart had 30 candies in his pocket. If he gave of the

AnnyKZ [126]

Answer:

3.33%

Step-by-step explanation:

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4 years ago

3x + 9y = -42 -3x + 2y = -2 The solution to the system is

AlladinOne [14]

x=−2 and y=−4

If you need explanation Just ask!

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4 years ago

How to solve the distributive property to express 27+60

Verizon [17]

(27)+(60)
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3 years ago

Does anyone know the minim value of the function f(x) =2x^2 -4x -6?. I’m online due to my quarantine and am looking for extra he

navik [9.2K]

Answer:

f(x) = - 8

Explanation:

The given function is

f(x) =2x^2 -4x -6

The first step is to find the derivative of the function. Recall, if

y = ax^b

y' = abx^(b - 1)

Thus,

f'(x) = 4x - 4

We would equate f'(x) to zero and solve for x. We have

4x - 4 = 0

4x = 4

x = 4/4

x = 1

We would substitute x = 1 into the original function and solve for f(x) or y. It becomes

f(1) =2(1)^2 -4(1) - 6 = 2 - 4 - 6

f(1) = - 8

Thus, the minimum value is f(x) = - 8

4 0

1 year ago

Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years sinc

nekit [7.7K]

Answer:

Hello,

Step-by-step explanation:

Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years since 1990. (a) what is the population expected to equal in year 2000 (b) determine the expression for the instantaneous rate of change in the population (c) what is the instantaneous rate of change in the population expected to equal in year 2000.

$P(t)=125*e^{0.035*t}\\a)\\P(2000)=125*e^{0.035*(2000-1990)}=177.38...\\\\b)\\P'(t)=125*0.035*e^{0.035*t}\\\\c)\\\\P'(2000)=125*0.035*e^{0.035*(2000-1990)}=6.2084...$

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3 years ago