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Nuetrik [128]
2 years ago
14

Find the distance between -7/8 and 3/8 on a number line

Mathematics
1 answer:
natulia [17]2 years ago
3 0
The distance is ten because first you minus the -7 to bring you to 0/8 and then you jump over 3 more to give you your distance
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What is the measure of ∠DEG?<br> A) 133° <br> B) 103° <br> C) 77° <br> D) 67°
nordsb [41]
Hmmmmmm
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3 0
3 years ago
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$32 is 8% of what amount?
e-lub [12.9K]

Answer:

$32 is 8% of 400

Step-by-step explanation:

Have a good day :)

4 0
3 years ago
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Maria scored 72, 97, and 82 on her first three math tests. She wants to have a mean score of 82 for the quarter. How many points
Rom4ik [11]

Answer:

<em>She needs </em><em>77 </em><em>on her last test to earn an 82 for the quarter.</em>

Step-by-step explanation:

Maria scored 72, 97, and 82 on her first three math tests.

She wants to have a mean score of 82 for the quarter.

Let us assume that she must score x on her last test to earn an 82 for the quarter.

So the average score will be,

=\dfrac{72+97+82+x}{4}

But the average score is given as 82, so

\Rightarrow \dfrac{72+97+82+x}{4}=82

\Rightarrow 72+97+82+x=82\times 4

\Rightarrow 72+97+82+x=328

\Rightarrow x=328-72-97-82

\Rightarrow x=77

3 0
2 years ago
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Write the equation of the line through the points (4,5) and (12,9)
Umnica [9.8K]

Answer:

 y=1/2+1

Step-by-step explanation:

1) Y2-Y1 over X2-X1

<u>9-5=4</u>

12-4=8

4/8 simplify the answer= 1/2

m=1/2

2) subtitute the simplification to one of the points.

y=mx+b

5=1(4)+b

5=4=b

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7 0
3 years ago
Reflection Over Parallel Lines Please complete the attached reflection. Thanks!
Allushta [10]

Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

A)

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

reflection over y = -1

Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)

4 0
3 years ago
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