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alina1380 [7]
3 years ago
6

the length of a diagonal of a square field is 220 metres find the length of a side in metres and the area of the field in hectar

es ​
Mathematics
1 answer:
andre [41]3 years ago
7 0

Answer:

Step-by-step explanation:

h^2=x^2+y^2, since this is a square x=y=s so

220^2=2s^2

2s^2=48400

s^2=24200

s=24200^(1/2)m (exact)

s=155.56m (rounded to nearest hundredth of a meter)

One hectare is equal to 10000m^2

A=24200m^2(h/10000m^2)

A=2.42 hectares

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The product of a number and four, increased by one, is at least 7.
faust18 [17]

Answer:

4/6

Step-by-step explanation:

a number which means "x" or u can name any variable u want

so the product of a number and four means

X×4

the increased by one or plus one

X×4+1

is at least 7

X(4)+1=7

4x+1=7

4x=7-1

4x=6

x=4/6

i guess so

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5 0
3 years ago
Read 2 more answers
the angle theta is located in quadrant 1 and cos of theta is 3/8. what is the value of sin of theta ?
ra1l [238]

Answer: sin of theta = (√55)/8

Step-by-step explanation:

Cosine is the x-value divided by the hypotenuse. We now know that since cosine is 3/8, that the hypotenuse is 8. In order to find the third side of the triangle (which would be the v-value), we must use Pythagorean theorem. The third side is square root 55. Sine equals the y-value divides by the hypotenuse. We know both of those values, so Sine of theta = square root of 55 divided by 8.

8 0
3 years ago
Mhanifa Plz help me with this thank you!
Ivanshal [37]

Answer:

D

Step-by-step explanation:

This is an example of the Pythagorean theorem.

In triangle BEH, the sum of the squares of the sides of the two smaller sides, BE and BH is equal to the longest side squared, EH.

8 0
3 years ago
Can someone solve this
Licemer1 [7]

Answer:

14w


Step-by-step explanation:


3 0
3 years ago
A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price
Nataliya [291]

Answer:

a) P=3(120-s)+200

b) 215 \leq P \leq 290

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

s) Create an equation to express the increase on the price tickets and the number of seats sold

s number of seats, if w analyze the info given the number of seats after increase the price is given by 120-s.

And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.

We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

P-200=3(120-s)

So then our linear equation is given by:

P=3(120-s)+200

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?

So for this case we just need to replace the limits into the linear equation and see what we got:

P_L=3(120-90)+200=290

P_U=3(120-115)+200=215

So the corresponding range of ticket prices is:

215 \leq P \leq 290

4 0
3 years ago
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