$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1400\\ r=rate\to 4.3\%\to \frac{4.3}{100}\dotfill &0.043\\ t=years\dotfill &7 \end{cases} \\\\\\ A=1400e^{0.043\cdot 7}\implies A=1400e^{0.301}\implies A\approx 1891.69\implies \stackrel{\textit{rounded up}}{A=1892}$

3 0

3 years ago

Please help me idk this

irina1246 [14]

Answer:

87 3/4

Step-by-step explanation:

in order to get your answer u will have to subtract

5 0

3 years ago

What errors did Amy make? Select all that apply.

Rashid [163]

She added the numerators
instead of multiplying them

you should also simplify the final answer

the correct answer would be -3 1/8 or -25/8 as an improper fraction.

7 0

3 years ago

Read 2 more answers

What equation represents this graph?

Alexxandr [17]

It should be d. y=2/3x+2

7 0

2 years ago

Read 2 more answers