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valkas [14]
2 years ago
7

What equation represents this graph?

Mathematics
2 answers:
nordsb [41]2 years ago
8 0
The answer is d. y=2/3x+2
Alexxandr [17]2 years ago
7 0
It should be d. y=2/3x+2
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I need help. See attachment for detail.
lesantik [10]

Answer:

4.5

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Solve for x 4(2x+9)=-44+8
Andreas93 [3]

Answer:

x=-9

Step-by-step explanation:

distribute 4 into the parentheses

8x+36=-44+8

add -44+8

and u get 8x+36=-36

subtract the 36 on both sides and leave u with

8x=-72

divide 8 on both sides

and ur answer is -9

i dont think this make sense but hope this helps

5 0
3 years ago
Read 2 more answers
HELP ME PLEASEEEEEEE
Tcecarenko [31]

Step-by-step explanation:

You must first add 20 to all inqualies, leaving u with 0 is greater than or equal to 2x which is also greater than or equal to 40.

Divde everything by 2 to get rid of the 2 from the x

0 divided by 2 is 0, 2x divded by 2 is x, 40 divided by 2 is 20.

Thats the answers

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B2%7D%7B15y%7D%20%20%2B%20%20%5Cfrac%7B3%7D%7B5y%20%7B%7D%5E%7B3%7D%20%7D" id="
Xelga [282]

Answer:

2y²   +   9

---------------

      15y³

Step-by-step explanation:

Start by identifying the LCD, and then change each fraction so that its denominator is the LCD.

Here the LCD is 15y³, which is evenly divisible by 15y and 5y³.

Focus now on the first fraction:  2 / (15y).  Multiplying numerator and denominator of this fraction by y² results in

y²·2          2y²

--------- → ----------

y²·15y       15y³           ←This is the correct LCD

Multiplying numerator and denominator of the second fraction by 3 results in:

   3·3            9

------------ → ---------

 3·5y³         15y³          ←This is the correct LCD

So now those two original terms look like:

 2y²         9

--------- + --------

 15y³       15y³

and this can be written in simpler form as:

2y²   +   9

---------------

      15y³

3 0
3 years ago
Two more than a number is less than 14. 2 + n less-than-or-equal-to 14 2 + n less-than 14 2 + n greater-than-or-equal-to 14 2 +
statuscvo [17]

Answer:

x+2 < 14 | -2

x < 12

2+n <= 14 | -2

n <= 12

2+n < 14 | -2

n < 14

2+n >= 14 | -2

n >= 12

2+n > 14 | -2

n > 14

8 0
3 years ago
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