4 years ago

Help me with this questions please. I will give you 15 points.

Mathematics

1 answer:

alexgriva [62]4 years ago

5 0

4) the answer is d

5) the answer is a

6) the answer is b

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Enter the solution to the inequality in the box.<br><br><br><br> 8+4(x−3)+3x≤24

xxMikexx [17]

8+4x-12+3x<=24
-4+7x<=24
7x<=28
X<=4

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3 years ago

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Help I will give out

Galina-37 [17]

Answer:

x = 9

Step-by-step explanation:

The line splits the sides of the triangle in proportion (the ratios of the pieces is the same for both sides).

Setup:

$\frac{8}{3x+1}=\frac{2}{x-2}$

"Cross multiply."

$2(3x+1)=8(x-2)\\6x+2=8x-16\\18=2x\\9=x$

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3 years ago

Mr. Brown has 20 students in his English 6 class. There are 15 boys and 5 girls. If he puts all their names in a hat and draws o

WINSTONCH [101]

Answer:

Divide

Step-by-step explanation:

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3 years ago

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every 3 days William has to take medication for his back. Every 7 days he has to take medication for asthma. On what day will Wi

S_A_V [24]

Okay, well we're gonna find the LCM (least common multiple)

3: 3, 6, 9, 12, 15, 18, 21

7: 7, 14, 21

So...21 days

4 0

4 years ago

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Bill can buy jags, jigs and jogs for $\$1$, $\$2$ and $\$7$ each, respectively. What is the largest number of jogs he can purcha

bekas [8.4K]

Answer:

6 jogs

Step-by-step explanation:

To spend exactly $50

Jags = $1

Jigs = $2

Jogs = $7

If he must buy atleast 1 of each and still spend exactly $50

Hence, the largest number of jogs he can buy can be modeled as :

First obtain the multiples of 7 up to 50

Multiple of 7 up to 50

7 : 7, 14, 21, 28, 35, 42, 49

If $49 is spent on jigs, then he won't be able to purchase jigs.

Hence, the largest amount he can spend on jogs is $42

Thus, he can buy $42 / $7 = 6 jogs

The $8 left can be spent on jigs and jags

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3 years ago