Answer: I don't know.
Step-by-step explanation:
I don't know.
In an arithmetic sequence:
Tn=t₁+(n-1)d
t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d
t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d
Therefore:
3t₁+12d=300 (1)
t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d
t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d
Therefore:
3t₁+45d=201 (2)
With the equations (1) and (2) we make an system of equations:
3t₁+12d=300
3t₁+45d=201
we can solve this system of equations by reduction method.
3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
-33d=99 ⇒d=99/-33=-3
3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112
Threfore:
Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n
Now, we calculate T₁₈:
T₁₈=115-3(18)=115-54=61
Answer: T₁₈=61
Y = 7
Explication pas à pas:
x est -3 donc -3 et connectez le x.
Y = -1 / 3 (-3) +5.
Y = 1 + 5
Y = 7
Answer:
18 smaller bags
Step-by-step explanation:
Each one pound bag becomes 3 one-third pound bags.
So 6 one pound bags will become 6×3=18 one-third pound bags.
Answer:
a. Function 1
b. Function 3
c. Function 2, Function 3 and Function 4
Step-by-step explanation:
✔️Function 1:
y-intercept = -3 (the point where the line cuts across the y-axis)
Slope, using the two points (0, -3) and (1, 2):

Slope = 5
✔️Function 2:
y-intercept = -1 (the value of y when x = 0)
Slope, using the two points (0, -1) and (1, -4):

Slope = -3
✔️Function 3: y = 2x + 5
y-intercept (b) = 5
Slope (m) = 2
✔️Function 4:
y-intercept = 2
Slope = -1
Thus, the following conclusions can be made:
a. The function's graph that is steepest is the function whose absolute value of its slope is greater. Therefore Function 1 is the steepest with slope of 5
b. Function 3 has a y-intercept of 5, which is the farthest from 0.
c. Function 2, Function 3, and Function 4 all have y-intercept that is greater than -2.
-1, 5, and 2 are all greater than -2.