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UNO [17]
3 years ago
10

You work 40 hours a week at a factory and make $2.00 per piece you create. It takes you

Mathematics
2 answers:
saul85 [17]3 years ago
4 0

Answer:

$400

Step-by-step explanation:

S x H  = (1 x 5 x 2) x 40

S x H  = (1 x 10)  x 40

S x H  = 10 x 40

S  =  400

S  = $400    H = 40

matrenka [14]3 years ago
3 0

Answer:

400

Step-by-step explanation:

1 hour = 5 pieces • $2

1 hour = $10 bcas each piece you make is $2

40 hours = $400 because you get $10 per week

You earn $400 per week

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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
Please help
Svetllana [295]

The midpoint of the line segment joining points S (8,3) and T (2,-1) is (5, 1)

<h3>How to determine the midpoint of the line segment joining the points?</h3>

The points are given as:

S(8,3) and T(2,-1)

The midpoint of the line segment joining points S(8,3) and T(2,-1) is calculated as:

Midpoint = 0.5 * (x1 + x2, y1 + y2)

So, we have

Midpoint = 0.5 * (8 + 2, 3 - 1)

Evaluate the sum

Midpoint = 0.5 * (10, 2)

Evaluate the product

Midpoint = (5, 1)

Hence, the midpoint of the line segment joining points S (8,3) and T (2,-1) is (5, 1)

Read more about midpoint at:

brainly.com/question/24311350

#SPJ1

8 0
2 years ago
It is estimated that 75% of the students at Ryder Middle School are involved in athletics or
Fittoniya [83]
B is the right answer
6 0
3 years ago
juan went to the sporting goods store. he spent $14 on a batting glove. he spent half of the remaining money on a football. late
Nuetrik [128]

Answer: 38 dollars

Step-by-step explanation:

  • work in reverse (include dollar sign in your answer, I can't get it on my keyboard)
  • 10  + 2 = 12
  • 12 x 2 = 24
  • 24 + 14= 38
4 0
2 years ago
On an algebra test, the highest grade was 42 points higher than lowest grade.
12345 [234]
You didn’t put the question in
4 0
3 years ago
Read 2 more answers
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