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LenKa [72]
3 years ago
8

Cuanto es la sexta parte? de 7000

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0
1166
is your answer mate
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Given 11 different natural numbers, none greater than 20. Prove that two of these can be chosen, one of which divides the other.
frosja888 [35]

Answer:11 honestly have no idea but im going to give my best answer it is 31

4 0
3 years ago
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What is 3 (x-6) +2 ≥ 5x - 4
Stells [14]

Answer:

-6 <u>></u> x

Step-by-step explanation:

3 (x-6) +2 ≥ 5x - 4

3x-18 + 2 <u>></u> 5x - 4

3x - 18 <u>></u> 5x - 6

-18 <u>></u> 2x - 6

-12 <u>></u> 2x

-6 <u>> </u>x

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3 years ago
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7. Triangle FIP was dilated by a scale factor of centered at the origin to
Assoli18 [71]

Answer:

AB is parallel to A'B'.

DO,1/2 (1/2x, 1/2y) =

The distance from A' to the origin is half the distance from A to the origin.

Step-by-step explanation:

6 0
2 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
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Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

4 0
3 years ago
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