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3 years ago

8

Cuanto es la sexta parte? de 7000

1 answer:

hodyreva [135]3 years ago

4 0

1166
is your answer mate

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(x2 + 1) dy /dx + 3x(y − 1) = 0, y(0) = 3 how do i go about solving this mess

monitta

Consider, pls, this option.

7 0

3 years ago

Quadrilateral KLMN is a rectangle. The coordinates of L are L(1,-4) and the coordinates of M are M(3,-2) find the slopes of side

m_a_m_a [10]

We can start by finding the gradient of LM
$m= \frac{ y_{2}- y_{1} }{x_{2} - x_{1} } = \frac{-2--4}{3-1} = \frac{2}{2}=1$

Two perpendicular lines will meet the requirement $m_{1}$ × $m_{2}$ =-1
Two parallel lines have equal gradients

NM is perpendicular to LM, hence the gradient of NM is -1
KN is a line that is parallel to NM, hence the gradient is 1
KL is perpendicular to LM, hence the gradient of KL is -1

5 0

3 years ago

Read 2 more answers

30=7r+5 what’s does r stand for

harkovskaia [24]

Answer:

An unknown variable

Step-by-step explanation:

r is an unknown variable -> the equation is used to solve for it.

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3 years ago

Read 2 more answers

Most people Just most people in the nine states use feet in miles to measure distance in there every day lives why do you scient

babunello [35]

The third answer should be the right one

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3 years ago

The x intercepts of the function f(x) = 2x(x-5)^2(x+4)^3<br> are…

Leokris [45]

Answer:

$\boxed{\sf x- intercepts = 0 , 5 \ and \ -4}$

Step-by-step explanation:

A function is given to us and we need to find the x Intercepts of the graph of the given function . The function is ,

$\sf \implies f(x) = 2x( x - 5 ) ^2(x+4)^3$

For finding the x intercept , <u>equate the given function with 0, we have ;</u>

$\sf \implies 2x ( x - 5 )^2(x+4)^3= 0$

Equate each factor with 0 ,

$\sf \implies 2x = 0$

Divide both sides by 2 ,

$\sf \implies\bf x = 0$

Again ,

$\sf \implies ( x - 5)^2=0$

Taking squareroot on both sides,

$\sf \implies x - 5 = 0$

Add 5 to both sides,

$\sf \implies \bf x = 5$

Similarly ,

$\sf \implies \bf x = -4$

<u>Hence</u><u> the</u><u> </u><u>x </u><u>Intercepts</u><u> </u><u>are </u><u>-</u><u>4</u><u> </u><u>,</u><u> </u><u>0</u><u> </u><u>and </u><u>5</u><u> </u><u>.</u>

{ See attachment also for graph } .

3 0

3 years ago