Cuanto es la sexta parte? de 7000

A town recently dismissed 9 employees in order to meet their new budget reductions. The town had 7 employees over 50 years of ag

raketka [301]

Answer: 0.1340

Step-by-step explanation:

The binomial distribution formula is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$ , where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.

Given : The number of employees over 50 years of age =7

The probability of employees over 50 years of age = $\dfrac{7}{7+15}=0.318$

Number of dismissed employees : n= 9

Now, the required probability will be :

$P(x =1)=^{9}C_1(0.318)^{1}(1-0.318)^{9-1}\\\\=(9)(0.318)(1-0.318)^{8}=0.133950588714\approx0.1340$

Thus, the probability that exactly 1 employee was over 50 = 0.1340

3 0

2 years ago

The function f(x) = x2 has been translated 9 units up and 4 units to the right to form the function g(x). Which represents g(x)?

Inga [223]

For this case , the parent function is given by [tex f (x) =x^2
[\tex]
We apply the following transformations
Vertical translations :
Suppose that k > 0
To graph y=f(x)+k, move the graph of k units upwards
For k=9
We have
[tex]h(x)=x^2+9
[\tex]
Horizontal translation
Suppose that h>0
To graph y=f(x-h) , move the graph of h units to the right
For h=4 we have :
[tex ] g (x) =(x-4) ^ 2+9
[\tex]
Answer :
The function g(x) is given by
G(x) =(x-4)2 +9

8 0

3 years ago

Read 2 more answers

Someone help and PLEASE make sure it’s right

lara31 [8.8K]

Answer:

Acute angle, doesn't have a 90 degree angle to be a right triangle, neither a wide angle to be an obtuse triangle.

3 0

2 years ago

In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

Viktor [21]

Answer:

$p_v =P(t_{(63)}>2.5)=0.0075$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=45$ represent the mean height for the sample

$s=16$ represent the sample standard deviation for the sample

$n=64$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=64-1=63$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(63)}>2.5)=0.0075$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

6 0

2 years ago

Find the value for the following determinant.<br><br> 5<br> -5<br> -11

s2008m [1.1K]

Answer:

i think -11

Step-by-step explanation:

5 0

2 years ago

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