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zheka24 [161]
3 years ago
10

The average mass of an ant is approximately 3 × 10 − 3 grams. The average mass of a giraffe is approximately 2 × 10 3 kilograms.

About how many times more mass does a giraffe have than an ant?
Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0

Given that average mass of an ant = 3 \times 10^{-3}grams.

Given that average mass of a giraffe = 2 \times 10^{3} Kilograms.

Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.

Like convert kilogram into gram or gram into kilogram.

I'm going to convert kilogram into gram using formula

1 Kg = 1000 g


So the average mass of a giraffe = 2 \times 10^{3} *10^3 grams.


Now we just need to divide mass of giraffe by mass of ant to find the answer.

\frac{2 \times 10^{3} *10^3 }{3 \times 10^{-3} }

= \frac{2 \times 10^{3} *10^3 *10^{3}}{3  }

= \frac{2 \times 10^{3+3+3}}{3  }

= \frac{2 \times 10^9}{3  }

= \frac{2}{3  } \times 10^9

=666666666.667

Hence final answer is \frac{2}{3  } \times 10^9 which is approx 666666666.667.

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4 0
3 years ago
Zach has a terrarium with the dimensions of 20 by 8 and the terrarium was filled with 3 inches of sand.Zach gets a new terrarium
Vladimir79 [104]

Answer: the sand in the new terrarium is 2 inches deep.

Step-by-step explanation:

Zach has a terrarium with the dimensions of 20 by 8 and the terrarium was filled with 3 inches of sand. It means that the volume of sand that this terrarium contains is

20 × 8 × 3 = 480 inches³

Zach gets a new terrarium that is larger with the dimensions of 10 by 24. If Zach moved the existing sand in the new terrarium and the height of the sand is represented by h, then the volume of sand into he new terrarium is

10 × 24 × h = 240h

Since the volume of sand in both terrariums is equal, then

240h = 480

h = 480/240

h = 2 inches

7 0
3 years ago
Simplify the following expression.
Katyanochek1 [597]
Where is the expression?
3 0
3 years ago
A rectangle and an equilateral
jek_recluse [69]

Answer:

The area of the rectangle = 50 cm^2.

Step-by-step explanation:

Let the shortest side of the rectangle be x cm.

Perimeter of the rectangle is:

2x + 2(x + 5).

Perimeter of the triangle =  3 * 2x.

As they have the same perimeter:

2x + 2(x + 5) = 3*2x

2x + 2x + 10 = 6x

6x - 2x - 2x = 10

2x = 10

x = 5 cm.

So the area of the rectangle = x(x + 5)

= 5 * 10

= 50 cm^2.

4 0
3 years ago
What is the approximate area of the figure?
melisa1 [442]

Option D:

The approximate area of the figure is 109.6 square feet.

Solution:

The figure is splitted into three shapes.

One is rectangle and the other two is semi-circles.

Diameter of the semi-circle = 5 feet

Radius of the semi-circle = 5 ÷ 2 = 2.5 feet

Area of the semi-circle = \frac{1}{2}\pi r^2

                                      $=\frac{1}{2}\times 3.14\times (2.5)^2

Area of the semi-circle = 9.8 square feet

Area of 2 semi-circles = 2 × 9.8

Area of 2 semi-circles = 19.6 square feet

Length of the rectangle = 18 feet

Width of the rectangle = 5 feet

Area of the rectangle = length × width

                                    = 18 × 5

Area of the rectangle = 90 square feet

Area of the figure = Area of 2 semi-circles + Area of the rectangle

                              =  19.6 square feet + 90 square feet

                              = 109.6 square feet

The approximate area of the figure is 109.6 square feet.

Hence Option D is the correct answer.

4 0
3 years ago
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