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RideAnS [48]
3 years ago
14

Please help with this question

Mathematics
1 answer:
natita [175]3 years ago
8 0

Answer:

  12\sin{(2\theta)}\cos{(\theta)}

Step-by-step explanation:

The appropriate trig identity is ...

  \sin{a}+\sin{b}=2\sin{\left(\dfrac{a+b}{2}\right)}\cos{\left(\dfrac{a-b}{2}\right)}

Here, you have a scale factor of 6 and a=3θ, b=θ. Filling in these values gives ...

  6\sin{3\theta}+6\sin{\theta}=12\sin{\left(\dfrac{3\theta+\theta}{2}\right)}\cos{\left(\dfrac{3\theta-\theta}{2}\right)}\\\\=12\sin{(2\theta)}\cos{(\theta)}

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