Ask question

Ask question

All categories

3 years ago

8

On the coordinate grid, the graph of y = RootIndex 3 StartRoot negative x minus 1 EndRoot is shown. It is a reflection and trans

lation of y = RootIndex 3 StartRoot x EndRoot. On a coordinate plane, a cube root function goes through (negative 2, 1), has an inflection point at (negative 1, 0), and goes through (7, negative 2). What is the range of the graphed function? {x |-2 < x < 2} {y |-2 < y < 2} {x | x is a real number} {y | y is a real number}

1 answer:

Thepotemich [5.8K]3 years ago

5 0

Answer:

{y | y is a real number}

Step-by-step explanation:

Just did the test on edgenuity

You might be interested in

1 euro = 0.84 sterling. A hotel cost 630 sterling how much will that cost in euro's

Dmitry_Shevchenko [17]

630 sterling * 1 euro / 0.84 sterling

630 sterling divided by 0.84 sterling = 750 euros

4 0

3 years ago

Solve for y:<br> x + 2y = -8<br><br> y=-1/2x+4<br> y=-1/2x-4<br> y=-2x - 4<br> y=1/2x-4

adelina 88 [10]

Answer:

x + 2y = -8 = y = -4 - 1/2x

y= -1/2x + 4 = y = 4

y= -1/2x - 4 = y = -4

y=-2x - 4 = y = -4

y=1/2x-4 = y = -4

Step-by-step explanation:

(x + 2y = -8 = y = -4 - 1/2x)

$x+2y=-8\\2y=-8-x\\y=-4-\frac{1}{2}x\\$

4 0

2 years ago

Solve the equation. StartFraction dx Over dt EndFraction equals StartFraction 1 Over x e Superscript t plus 7 x EndFraction An i

MAVERICK [17]

Answer:

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

Step-by-step explanation:

We are given that

$\frac{dx}{dt}=\frac{1}{xe^{t+7x}}$

We have to find the implicit function

Using separation variable method

$\frac{dx}{dt}=\frac{1}{xe^t\cdot e^{7x}}$

By using property $x^a\cdot x^y=x^{a+y}$

$xe^{7x}dx=e^{-t}dt$

By using property $\frac{1}{x^a}=x^{-a}$

Taking integration on both sides

$\int xe^{7x}dx=\int e^{-t}dt$

Parts integration method

$\int u\cdot v dx=u\int vdx-\int (\frac{du}{dx}\int vdx)dx$

By parts integration method

$x\int e^{7x}dx-\int (\frac{dx}{dx}\int e^{7x}dx)dx=-e^{-t}+C$

Using formula $\int e^{ax} dx=\frac{e^{ax}}{a}+C$

$\frac{xe^{7x}}{7}-\frac{1}{7}\int e^{7x}dx=-e^{-t}+C$

$\frac{xe^{7x}}{7}-\frac{1}{49}e^{7x}+e^{-t}=C$

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

We are given that

$F(x,t)=C$

$F(x,t)=\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

8 0

2 years ago

"A new bakery offers decorated sheet cakes for children’s birthday parties and other special occasions. The bakery wants the vol

Darya [45]

Answer:

$w = 9 \text{ inches}\\l = 13\text{ inches}\\h = 3\text{ inches}$

Step-by-step explanation:

We are given the following in the question:

Volume of cake = 351 cubic inches

Let x inches be the width of cake.

Width of cake, w =

$x\text{ inches}$

Then, length of cake,l =

$(x + 4)\text{ inches}$

Height of cake,h =

$\dfrac{x}{3}\text{ inches}$

Volume of cake = Volume of cuboid

$V = lwh$

Putting values, we get:

$351 = x(x+4)(\dfrac{x}{3})\\\\1053 = x^3 + 4x\\x^3+4x^2-1053= 0\\\\\text{For x = 9}\\(9)^3+4(9)^2-1053= 0$

Thus, dimensions of cake are:

$w = 9 \text{ inches}\\l = 13\text{ inches}\\h = 3\text{ inches}$

3 0

3 years ago

X = 2y - 4<br> 7x + 5y = -66

madreJ [45]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers