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sammy [17]
4 years ago
9

Your dive computer indicates you need to make a mandatory decompression stop. You buddy's dive computer does not. You should: A.

Follow your buddy's dive computer and have yours repaired. B.You and your buddy should both follow the most conservative of the two dive computers C.. Make a decompression stop that splits the difference between what your buddy's computer requires and what yours does. D.None of the above.
Computers and Technology
1 answer:
Sati [7]4 years ago
7 0

Answer: Option C : Make a decompression stop that splits the difference between what your buddy's computer requires and what yours does.

Explanation:

Dive computers are battery-powered computers within a watertight and pressure resistant case. These computers track the dive profile by measuring time and pressure.

hence, making a decompression stop that splits the difference between what your buddy's computer requires and what yours does is the best option.

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The marvelous attribute about the gaming industry is that you can create a game in several different programming languages to ma
LenaWriter [7]

Answer:

D syntax

Explanation:

The marvelous attribute about the gaming industry is that you can create a game in several different programming languages to make it more appealing to novice and advanced-level coders. Yet, the unique distinction is that every single programming language has its own syntax.

7 0
2 years ago
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
7
Alex17521 [72]

Answer:

Number of CDs = 7

Explanation:

We know that

1 GB = 1024 MB

So it means the 4 GB of data can be interpreted as:

4 GB = 1024*4 MB

4GB = 4096 MB

So a DVD hold 4096 MB of data while a CD holds 650 MB of data.

We need to find how many CDs could hold 4096 MB of data, to make it equivalent to a DVD

Number of CDs = 4096/650

Number of CDs= 6.3

As a CD can not be 0.3, a whole 1 CD will be used.

Number of CDs = 7

4 0
3 years ago
IOS 0R ANDR0ID ???
Lera25 [3.4K]

Answer:

Both are awesome!

Explanation:

One thing we shouldn't do is downgrade others for having an android or calling someone basic because they have ios. Both have their pros and cons, but idk because I don't have a phone! Hehe. But my family primarily uses IOS.

3 0
3 years ago
One of the First-Generation Computer built in 1942 during the Second World War and fully utilized to compute Military Artillery
Temka [501]
ENIAC, in full Electronic Numerical Integrator and Computer, the first programmable general-purpose electronic digital computer, built during World War II by the United States. American physicist John Mauchly, American engineer J. Presper Eckert, Jr., and their colleagues at the Moore School of Electrical Engineering at the University of Pennsylvania led a government-funded project to build an all-electronic computer.

From Brittanica.com
7 0
3 years ago
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