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professor190 [17]
3 years ago
12

HELP ME PLEASE!!!!!!!!!!!!!HELP ME PLEASE!!!!!!!!!!!!!

Mathematics
2 answers:
Alina [70]3 years ago
4 0
Zhgyiojvfdtyuikbvfdtyhhh it’s b
kramer3 years ago
3 0
!!!!!!!! The answer would be B !!!!!!
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What calculation can I use to find 498 after a 6.1% decrease?
Sergio039 [100]

Answer:

b is the answer

Step-by-step explanation:

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3 years ago
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the area of a rectangle city park is 25/54 sqaure miles. the length of the park is 5/9 mile. what is the width in miles of the p
andreyandreev [35.5K]
A = lw

Plug in what we know:

25/54 = (5/9)w

Divide 5/9 to both sides or multiply by its reciprocal, 9/5:

25/54 * 9/5 = w

Multiply the numerators and denominators together:

225/270 = w

Simplify:

<span>w = 5/6</span>
6 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
Show the work and answer for 5550÷10 to the third power
emmainna [20.7K]
Well I know the answer is 555 because when ever you are dividing by ten move the decimal place u move the decimal 1 place to the left or just take out the 0 at the end
8 0
3 years ago
At first a price was decreased by 12%, then it was discounted again by an additional 5%. What is the percent of the total discou
olga_2 [115]
Hello there! I can help you! So we are decreasing a price by 12% and then doing it again by 5%. We would pay 88% of the original price and then 95% of that sale price. To execute this better, let's make a real-world situation. Say that Mariana wants to buy a new pair of shoes that originally costed $100. The store has a tag for 12% off and then an additional 5% discount at the counter. How much would she pay for the shoes? What total discount does she get? Let's start by multiplying 100 by 88%. 100 * 88% (0.88) is 88. That's the first part. Now, we multiply that number by 95% to find the price at the counter. 88 * 95% (0.95) is 83.6. That's the price with both discounts. Mariana would pay $83.60 for the shoes, but what about the percent discount total? Let's subtract that price from 100 and see what we get. 100 - 83.6 is 16.4. Percents are parts of 100, so we don't need to do anymore simplifying. There. The total amount of discount is 16.4%.
4 0
3 years ago
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