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WINSTONCH [101]
3 years ago
9

The number of seconds in a 40-hour work week can be calculated as follows:

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0
<h3>​The number of seconds in a 40-hour work week can be calculated as follows:</h3>

First we can calculate how many seconds there are in an hour:​

​Since 1 hour has 60 minutes and each minute has 60 seconds.

​Then 1 hour = 60 minutes * 60 seconds/1minute = 3,600 seconds.

​Now we have to multiply x 40 to calculate how many seconds there are in 40 hours.

​In a 40-hour work week = 40 hours * 3,600 seconds/1hour = 144,000 seconds

​Answer : 144,000 seconds there are in a 40-hour work week

​Hope this helps!​​​​

​\textit{\textbf{Spymore}}​​​​​​​

natita [175]3 years ago
6 0

40hrs*60mins/1hr=2400mins

2400mins*60secs/min=144,000secs

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Answer:

32.1%

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3 years ago
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard devi
kotykmax [81]

Answer:

0.35% of students from this school earn scores that satisfy the admission requirement.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.

This means that \mu = 1479, \sigma = 302

The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?

The proportion is 1 subtracted by the pvalue of Z when X = 2294. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2294 - 1479}{302}

Z = 2.7

Z = 2.7 has a pvalue of 0.9965

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0.0035*100% = 0.35%

0.35% of students from this school earn scores that satisfy the admission requirement.

6 0
3 years ago
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