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WINSTONCH [101]
3 years ago
9

The number of seconds in a 40-hour work week can be calculated as follows:

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0
<h3>​The number of seconds in a 40-hour work week can be calculated as follows:</h3>

First we can calculate how many seconds there are in an hour:​

​Since 1 hour has 60 minutes and each minute has 60 seconds.

​Then 1 hour = 60 minutes * 60 seconds/1minute = 3,600 seconds.

​Now we have to multiply x 40 to calculate how many seconds there are in 40 hours.

​In a 40-hour work week = 40 hours * 3,600 seconds/1hour = 144,000 seconds

​Answer : 144,000 seconds there are in a 40-hour work week

​Hope this helps!​​​​

​\textit{\textbf{Spymore}}​​​​​​​

natita [175]3 years ago
6 0

40hrs*60mins/1hr=2400mins

2400mins*60secs/min=144,000secs

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5 0
2 years ago
Why can't you compare 5 minutes in 240 seconds without making some kind of change
grin007 [14]
You have to have the same unit of measure. Here your units are "minutes" and "seconds". In order to compare the two, you must change to 240 seconds into minutes (dividing by 60 = 4 mins) OR change the 5 minutes into seconds (multiply by 60 to give you 300 seconds)
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3 years ago
areas of four triangles are 40 cm^2, 90 cm^2, 202.5 cm^2 and 455.6 cm^2 are continue in sequence. the enlargement factor is 1.5,
maw [93]

Answer:

9th Triangle

Step-by-step explanation:

Given the area of four triangles:40 cm^2, 90 cm^2, 202.5 cm^2 \:and\: 455.6 cm^2

If the Scale factor is 1.5.

This is a geometric sequence and the common ratio is 1.5 X 1.5.

Therefore, the area of any n triangle can be determined using the function:

A(n)=40\cdot1.5^{2(n-1)}

We want to determine which triangle has an area greater than 15000cm^2.

When A(n)=15000

40\cdot1.5^{2(n-1)}>15000\\1.5^{2(n-1)}>\frac{15000}{40} \\1.5^{2(n-1)}>375\\\text{Change to Logarithm form}\\2(n-1)>Log_{1.5}375\\\text{Applying logarithm change of base to base 10 law}\\2(n-1)>\frac{Log 375}{Log 1.5} \\2n-2>14.62\\2n>14.62+2=16.62\\n>8.31

Therefore, the 9th triangle has an area greater than 15000cm^2.

5 0
3 years ago
What happens to the value of the expression 150-j150−j150, minus, j as jjj decreases?
nikklg [1K]

Answer:

The value of the expression increases as j decreases

Step-by-step explanation:

Let f(j) = 150 - j150 - j150

f(j) = 150 - j300

As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.

For example:

When j = 1, f(j) = 150 - (300*1) = -150

When j = 0.5, f(j) = 150 - (300*0.5) = 0

When j = 0. f(j) = 150 - (300*0) = 150

It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases

4 0
3 years ago
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