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3 years ago

1. When Mrs. Weeks bought all of the baseballs and softballs, she paid

Mathematics

1 answer:

Lostsunrise [7]3 years ago

5 0

Answer:

1) $104

2) 7(28) + 5(20) + c= 4(100)

3) 21 more balls

4) (135/9) + (48/6)

Step-by-step explanation:

The question is incomplete. The total number of balls wasn't stated neither was the cost of each ball.

To determine the answers to the questions above, Let's look at the following question:

Type of Ball:

football basketball baseball softball

Cost per Ball:

$8.00 $9.00 $7.00 $5.00 respectively

Total Number of Balls: 32 36 28 20 respectively

1. When Mrs. Weeks bought all of the baseballs and softballs, she paid for them using four $100.00 bills. How much change did she receive?

2. Write expressions that include parentheses and order of operations to show how to find the answer. Show your work.

3. After school began, Mrs. Weeks realized that she needed more

basketballs and footballs. If she spent $135.00 on basketballs and

$48.00 on footballs, how many more balls did she purchase?

4. Write expressions the include parentheses and order of operations to show how to find the answer. Show your work.

Solution:

Total number of balls = 32+36+28+20 = 116

Cost per ball for football = $8.00

Cost per ball for basketball =$9.00

Cost per ball for baseball =$7.00

Cost per ball for softball =$5.00

1) number of balls for baseball = 28

number of balls for softball = 20

Cost of 28 baseball = 28(7) = $196

Cost of 20 baseball = 20(5) = $100

She paid with = four $100.00 bills

= 4×100 = 400

Change she received = 400-(100+196) = 400-296

= $104

2) 7(28) + 5(20) + c= 4(100)

Where c = the change she collected

196 + 100 +c = 400

296 + c = 400

c = 400-296

c = $104

3) she spent $135.00 on basketballs

$48.00 on footballs

Number of basketballs bought = 135/9

= 15 basketballs

Number of footballs bought = 48/8

= 6 footballs

Total number of balls purchased = 15+6 = 21

She purchased 21 more balls

4) (135/9) + (48/6)

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