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<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
M = -4 -4 / 5- 3 = -8/2 = -4
y = -4x + b
4 = -12 + b
b = 16
y = -4x + 16
Answer:
The area is 452.39
The Circumference is 75.36
Step-by-step explanation:
Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3
<u>Solution:</u>
We have been given two equations which are as follows:
3x - 4y = -24 ----- eqn 1
x + 4y = 8 -------- eqn 2
We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.
We rearrange eqn 2 as follows:
x + 4y = 8
x = 8 - 4y ------eqn 3
Now we substitute eqn 3 in eqn 1 as follows:
3(8 - 4y) -4y = -24
24 - 12y - 4y = -24
-16y = -48
y = 3
Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:
x = 8 - 4(3)
x = 8 - 12 = -4
Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.
