Answer:
First: 15
Second: 21
Third: 45
Step-by-step explanation:
In order to create the equation we need to represent the evenings with an alebraic term, in thsi case we are going to represent the second evening with an X
Second evening:x
The first night she got 6 fewer calls than the second: Second-6=x-6
The third night she received 3 times the first: 3(first night)=3(x-6)
The equation is First Night plus second night plus third night equals 81.
So the first evening he received 15 calls, the second he received 21 and the third one he received 45.
Answer:
The answer is 9996
Step-by-step explanation:
Using the identity (x+a)(x+b) = x ^2 +(a+b)x+ab
Writing 102 as 100+2 and 98 as 100−2
Hence (100+2)(100−2) = 100 ^2 +[2+(−2)]100+(2)(−2)
= 10000+(0)100−4
= 9996
The answer is 9996
Answer:
4 and 1/3
Step-by-step explanation:
3 can go into 13 4 times with one left over
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hope this helps
ANSWER
to the nearest hundredth.
EXPLANATION
We have the equation,
Which can be rewritten as
The question demands the use of the quadratic formula.
Comparing this to the general quadratic equation;
The quadratic formula is given by;
We now substitute all the values in to the formula;
We simplify to obtain;
We now split the plus or minus sign to obtain;
This implies that;
Or
This will evaluate to;
Hence, the positive solution rounded to the nearest hundredth is
