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3 years ago

6

Write the 3 digit number that answers the riddle? I have the same hundreds digit as the ones digit. The value of my tens digit i

s 50. The value of my ones digit is 4. The number is ?

2 answers:

jok3333 [9.3K]3 years ago

4 0

<span>The answer is 454. Since the value of the ones digit is 4, the last digit is a 4. Next, since the ones digit is the same as the hundreds digit, the first digit would be 4. Finally, the middle digit is the tens place and would be 5 since the tens digit is 50.</span>

svetlana [45]3 years ago

3 0

Answer:

Step-by-step explanation:

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An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the

sdas [7]

Answer:

a

$n= 75, 582$

b

$n= 2300$

c

$n = 253$

Step-by-step explanation:

Generally the size of the sample sample space is mathematically represented as

$n = \left N } \atop {}} \right. C_r$

Where N is the total number of objects available and r is the number of objects to be selected

So for a, where N = 19 and r = 8

$n = \left 19 } \atop {}} \right. C_8 = \frac{19 !}{(19 - 8 )! 8!}$

$= \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}$

$n= 75, 582$

For b Where N = 25 and r = 3

$n = \left 25 } \atop {}} \right. C_3 = \frac{25 !}{(19 - 3 )! 3!}$

$= \frac{25 *24 *23 *22 ! }{22 ! \ 3!}$

$n= 2300$

For c Where N = 23 and r = 2

$n = \left 23 } \atop {}} \right. C_2 = \frac{23 !}{(23 - 2 )! 2!}$

$= \frac{23 *22 *21! }{21 ! \ 3!}$

$n = 253$

4 0

4 years ago

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

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4 years ago

Identify the slope as positive, negative, zero or undefined

slavikrds [6]

Answer:

Zero

Step-by-step explanation:

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3 years ago

18. An urn contains 3 red balls, 2 green balls and 1 yellow ball. Three balls are selected at random and without replacement fro

Goryan [66]

Answer:

27.77%

Step-by-step explanation:

The probability of not drawn a red ball is 3/6. The probability of not drawn a green ball is 4/6, and the probability of not drawn a yellow ball is 5/6. So, the probability of not drawn at least one color is the multiplication of the probabilities of each color, so (3/6)*(5/6)*(4/6) = 0.2777.

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3 years ago

If ED = 10 and DB = 3x-8, what is the length of EB<br><br> 1. 32<br> 2. 22<br> 3. 10<br> 4. 20

Debora [2.8K]

Based on the picture, we know that ED is equal to DB. Therefore:

2 times ED=EB
2(10)=20

EB is 20

4 0

4 years ago

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