Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
702.1
Step-by-step explanation:
Use the formula for the diagonal of a cuboid.
√(l^2+b^2+h^2)
√(33^2+56^2+33^2)
√5314
= 702.125345
The scenario described above is like dividing a right cone from the vertex down to the center for the base. The polygon that can be formed from the division or in this case slicing is a triangle. Thus, the answer to this item is letter B.
-4(9)(-5) = (-36)(-5) because -4(9) = -36. (-36)(-5) = 180
The first number is x axis while the second is y
