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nekit [7.7K]
3 years ago
6

Write the 3 digit number that answers the riddle? I have the same hundreds digit as the ones digit. The value of my tens digit i

s 50. The value of my ones digit is 4. The number is ?

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
4 0
<span>The answer is 454. Since the value of the ones digit is 4, the last digit is a 4. Next, since the ones digit is the same as the hundreds digit, the first digit would be 4. Finally, the middle digit is the tens place and would be 5 since the tens digit is 50.</span>
svetlana [45]3 years ago
3 0

Answer:

Step-by-step explanation:

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Start at 3 and create a pattern with the rule add 2 what is the 5th rumber in the answer
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Answer:13

Step-by-step explanation:

3,5,7,9,11,13

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Find the value of Z in the following equation: 8Z = 64.<br> a. 72<br> B. 8<br> C. 512<br> D. 56
VLD [36.1K]
8Z = 64

Divide both sides by 8.

8Z/8 = 64/8

Z = 64/8

Z = 8


Your final answer is B. 8.
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The reduced cost for a decision variable that appears in a Sensitivity Report indicates the change in the optimal objective func
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Answer:C

Step-by-step explanation:

Looking at number line, the function value always range from positive value from 0 to negative numbers to -1

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1-1=............... HELP!!!!!!!!!!!!!!!!!!
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Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
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