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Darya [45]
4 years ago
7

How can I solve the Jose moped question because I am confused?

Mathematics
1 answer:
lana [24]4 years ago
3 0

Answer:

BRuh just send jose to the cleaners

Step-by-step explanation:

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Charlie is watching hot air balloons. balloon a has risen at a 50° angle. balloon b has risen at a 78° angle. if the distance fr
AfilCa [17]

The distance from Balloon A to Balloon B, d ≈ 1,052 feet

What is distance ?

  • Distance is defined to be the magnitude or size of displacement between two positions.
  • Note that the distance between two positions is not the same as the distance traveled between them.
  • Distance traveled is the total length of the path traveled between two positions. Distance traveled is not a vector.

The given parameters are;

The angle at which Balloon A rises, x° = 50° above horizontal

The angle at which Balloon B rises, y° = 78° above horizontal

The (vertical) distance of Balloon A to the ground, h = 1,000 ft.

The required parameter;

The distance from Balloon A to Balloon B, d

We find the distances of the balloons from Charlie and the angle between the balloon strings, θ, then apply cosine rule

Let,

The height of the balloon strings are equal

The distance of Balloon A to the ground, h₁ = The distance of Balloon B to the ground, h₂ = 1,000 ft.

The distance of the Balloon A  from Charlie, l₁, is given as follows;

l₁ × sin(x°) = h₁

∴ l₁ = h₁/(sin(x°))

Which gives;

l₁ = 1,000 ft./(sin(50°)) ≈ 1,305.41 ft.

l₁ ≈ 1,305.41 ft.

For Balloon B, we get;

h₁ = h₂ = 1,000 ft.

∴ l₂ = 1,000 ft./(sin(78°)) ≈ 1,022.34 ft.

l₂ ≈ 1,022.34 ft

The angle between the balloon strings, θ = 180° - (x° + y°)

∴ θ = 180° - (50° + 78°) = 52°

The angle between the balloon strings, θ = 52°

By cosine rule, we have;

d = √(l₁² + l₂² - 2 × l₁ × l₂ × cos(θ))

∴ d = √(1,305.41² + 1,022.34² - 2 × 1,305.41×1,022.34 × cos(52°)) ≈ 1,052 feet

Therefore, the distance from Balloon A to Balloon B, d ≈ 1,052 feet

Learn more about distance

brainly.com/question/15172156

#SPJ4

7 0
2 years ago
I need help with this question please help
forsale [732]

Answer:

<h2>282.857 in²</h2>

Step-by-step explanation:

The formula of a surface area of a cylinder:

S.A.=2\pi r^2+2\pi rH

r - radius

H - height

We have:

r = 5 in

H = 4 in

Substitute:

S.A.=2\pi(5^2)+2\pi(5)(4)=2\pi(25)+2\pi(20)\\\\=50\pi+40\pi=90\pi\ in^2

\pi\approx\dfrac{22}{7}

Substitute:

S.A.\approx90\cdot\dfrac{22}{7}=\dfrac{1980}{7}\approx282.857\ in^2

4 0
4 years ago
How do I find the square root of a monomial?​
Ugo [173]

Answer:

The square root of a monomial is equal to the square root of the numerical coefficient, multiplied by the literal factors, with the exponent of each literal factor divided by 2, and the sign of the answer is + or -.

Step-by-step explanation:

have a great day! Also may I sugest watching a kahn academy videos they are very helpful :)

4 0
3 years ago
Read 2 more answers
A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4
vlabodo [156]

Answer:

Therefore the diameter of the hole is 1.94 \times 10^{-3} m.

Step-by-step explanation:

Bernoulli's equation,

P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2

P₁ = P₂= atmospheric presser

\rho= density

\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2             [since P₁ = P₂]

\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)

\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2

\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2

\Rightarrow v^2_2- v^2_1=2g h                                [h_1-h_2=h]

Here   v_1\approx 0

\Rightarrow v^2_2=2g h

\therefore v_2=\sqrt {2gh

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole v_2 = \sqrt {2\times 9.8\times 10.4} m/s

                                                                                  =14.28 m/s.

Given, the rate of flow from the leak is 2.53\times 10^{-3} m^3/min

                                                               =\frac{2.53\times 10^{-3}}{60}  m^3/s

Let the diameter of the hole be d.

Then the cross section area of the hole is =\pi (\frac d2)^2

We know that,

The rate of flow = Cross section area × speed

\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28

\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}

\Rightarrow d= 1.94 \times 10^{-3}

Therefore the diameter of the hole is 1.94 \times 10^{-3} m.

4 0
4 years ago
Find the equation of the line use exact numbers
mart [117]

Answer:

y = -³/2x + 3

Step-by-step explanation:

To find the equation of the line in slope-intercept form, y = mx + b, we need to finder the slope (m) and the y-intercept (b).

✔️Slope (m) = ∆y/∆x

Using two points on the line, (0, 3) and (2, 0),

Slope = (0 - 3)/(2 - 0) = -3/2

Slope (m) = -³/2

✔️y-intercept (b) = 3 (this is the y-cooordinate of the point where the line intercepts the y-axis)

✔️To write the equation, substitute m = -³/2 and b = 3 into y = mx + b

This:

y = -³/2x + 3

4 0
3 years ago
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