Write the equation of a circle with center upper c left-parenthesis 4 comma negative 5 right-parenthesis that passes through upp
er p left-parenthesis 1 comma negative 2 right-parenthesis number .
1 answer:
The square of the distance between C(4, -5) and P(1, -2) is given by the Pythagorean theorem as
(4-1)² +(-5-(-2))² = 18
This is the square of the radius of the circle, so we can use it for r² in the formula
(x -h)² +(y -k)² = r² . . . . . . . circle of radius r and center (h, k)
Your circle has equation ...
(x -4)² +(y +5)² = 18
(4-1)² +(-5-(-2))² = 18
This is the square of the radius of the circle, so we can use it for r² in the formula
(x -h)² +(y -k)² = r² . . . . . . . circle of radius r and center (h, k)
Your circle has equation ...
(x -4)² +(y +5)² = 18
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Missing term = –2xy
Solution:
Let us first find the quotient of .
Taking common term xy outside in the numerator.
Both xy in the numerator and denominator are cancelled.
Thus, the quotient of is
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Given the quotient of is same as the product of 4xy and ____.
× missing term
Divide both sides by 4xy, we get
⇒ missing term =
Cancel the common terms in both numerator and denominator.
⇒ missing term = –2xy
Hence the missing term of the product is –2xy.