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olga_2 [115]
3 years ago
14

What is the GCF of 22,88,10,50?

Mathematics
1 answer:
RUDIKE [14]3 years ago
4 0
The answer is 2. hope thishelps
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Paul had 3.8 pounds of bananas and 2.1 pounds of apples. About how much fruit does he have in all?​
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5.9 pounds

Step-by-step explanation:

3.8 + 2.1 = 5.9

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The price of a laptop computer was $1,980. During a fair, the price was reduced by 30%. Find the price of the computer during th
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The computer is now worth 594 dollars.

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3 years ago
According to a study done by Otago University, the probability a randomly selected individual will not cover his or her mouth wh
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Answer:

47.52% probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth

Step-by-step explanation:

For each individual, there are only two possible outcomes. Either they cover their mouth when sneezing, or they do not. The probability of an individual covering their mouth when sneezing is independent of other individuals. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

According to a study done by Otago University, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267.

This means that p = 0.267

What is the probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth

10 individuals, so n = 10.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.267)^{0}.(0.733)^{10} = 0.0448

P(X = 1) = C_{10,1}.(0.267)^{1}.(0.733)^{9} = 0.1631

P(X = 2) = C_{10,2}.(0.267)^{2}.(0.733)^{8} = 0.2673

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0448 + 0.1631 + 0.2673 = 0.4752

47.52% probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth

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3 years ago
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