There are two equations and two variables. You can solve for each variable using either the elimination method or the substitution method. Here, I believe the elimination method would be best:
5a = -4b + 5
3a = -2b + 3
You can multiply the second equation by two, so the 4b and -4b in both equations will cancel each other out when you add them. So:
5a = -4b +5
6a = 4b +6
Add both equations together.
11a = 11
a = 1
Plug in the a value into any of the previous equations:
5(1) = -4b + 5
-4b = 0
b = 0
So, since we know that b = 0, 6b is also 0.
Answer:
8y^3+6y^2-29y+15
Step-by-step explanation:
the correct expression is
(4y − 3)(2y^2 + 3y − 5)
Given data
We have the expression
(4y − 3)(2y^2 + 3y − 5)
let us open bracket
8y^3+12y^2-20y-6y^2-9y+15
Collect like terms
8y^3+12y^2-6y^2-20y-9y+15
8y^3+6y^2-29y+15
5600 - 4420 = 1180....so there is a difference of 1180 in a period of (1998 - 1993) = 5 yrs.
1180/5 = 236 people per yr
so in 1998 the population was 5600.....in 2000 (2 yrs later) the population would be : 5600 + 236(2) = 5600 + 472 = 6072 <==
Answer:
°
Step-by-step explanation:
subtract 
form both sides
plz mark me brainliest. :0
Answer:
Step-by-step explanation:
hope this helps
