On the number line after 10 moves frog is at the integer -96.
Given that, a frog starts at 0 on a number line.
It jumps 100 units to the right then jumps 200 units to the left=+100-200=-100 (2 moves).
It then jumps 199 units to the right followed by 198 units to the left =-100+199-198=-99 (2 moves).
It then jumps 197 units to the right followed by 196 units to the left =-99+197-196=-98 (2 moves).
It then jumps 195 units to the right followed by 194 units to the left =-98+195-194=-97 (2 moves).
It then jumps 193 units to the right followed by 192 units to the left =-97+193-192=-96 (2 moves).
Hence, on the number line after 10 moves frog is at the integer -96.
To learn more about the integers visit:
brainly.com/question/15276410.
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Answer:

Step-by-step explanation:
<u>Step 1: Convert to Scientific Notation</u>
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Answer: 
I have a question just so u wont get it wrong and to see if im right but are you trying to get the missing number ???
Answer:
1050 g < weight ≤ 1150 g
Step-by-step explanation:
Let w represent the weight of the package in grams. The the number of 100-gram increments after the first 250 grams is given by ...
⌈(w-250)/100⌉ . . . . . . . where ⌈ ⌉ signifies the <em>ceiling</em> function
and the charges for a package exceeding 250 grams will be ...
0.65 + 0.10⌈(w -250)/100⌉ = 1.55
0.10⌈(w -250)/100⌉ = 0.90 . . . . . . . . subtract 0.65
⌈(w -250)/100⌉ = 9 . . . . . . . . . . . . . . . divide by 0.10
8 < (w-250)/100 ≤ 9 . . . . . . . . . . . . . . meaning of ceiling function
800 < w -250 ≤ 900 . . . . . . . . . . . . . multiply by 100
1050 < w ≤ 1150 . . . . . . . . . . . . . . . . . add 250
The weight in grams could be greater than 1050 and at most 1150 for a charge of $1.55.