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Ksenya-84 [330]
4 years ago
5

On September 1, Year 1, the Central Illinois University ticket office sold $1,800,000 worth of season basketball tickets. Ten ho

me games will be played: four games will be played during Year 1 and six games will be played during Year 2. What is the adjusted balance in Deferred Revenue account at December 31, Year 1?
Business
1 answer:
Alexxandr [17]4 years ago
4 0

Answer:

The adjusted balance in Deferred Revenue at the end of year 1 is $1,080,000.

Explanation:

Deferred revenue is also known as unearned revenue which means that income is received but not earned. In accrual basis accounting, we record revenues only after we deliver the goods or perform the services.

In this case, the $1,800,000 is received for 10 home games which means that per game we received 1,800,000/10 = 180,000.

Since only 4 games were played during the year, the revenue earned at the end of year 1 is: 180,000*4= 720,000

The remaining 6 games will be played in year 2 but we have already received the payment of games, so it will be considered as a Deferred Revenue. The amount of Deferred Revenue at the end of year 1 is:

⇒ 180,000*6 = 1,080,000

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If business leaders become optimistic about future sales and profits, they will __________ spending on plant and equipment, whic
posledela

Answer: increase - increase - fulfilled

Explanation: The attitude of optimism towards future sales and profits will increase spending on plants and equipments but in turn, there is increase in employment and income and, hence, their expectations are fulfilled.

5 0
4 years ago
Debra spends 22 hours a week studying in the gatton building. Debra currently has a 3. 7 gpa. If debra reduced her time studying
Musya8 [376]

Debra spends 22 hours a week studying in the Gatton building. Debra currently has a 3.7 GPA. If Debra reduced her time studying to 10 hours a week she would have a 2.7 GPA. If she only studied for 10 hours a week she could spend 12 hours working at Common Grounds for $9.25/hour. Debra's marginal cost in terms of dollars per week of improving her GPA from a 2. 7 to a 3. 7 will be $111.

What GPA manner?

Grade factor average (GPA) is the measure used to summarize your academic fulfillment at Griffith. After the publication of very last grades each trimester, your program and profession GPA are calculated, and will be used by the college to inform choices, including the following: educational progression.

Is a GPA 3.5 properly?

However, a grade factor common of three.5 and above is good in college. 3.5 GPA college students usually qualify for the dean's list and honors packages. The common GPA in four-year undergraduate courses in U.S. schools is 3.15. So, we will optimistically say that yes, a 3.5 GPA is good in university.

Can get into Harvard with a 3.5 GPA?

A 3.5 GPA may be surprisingly competitive and admission may be reasonably expected at many colleges, but it's no longer the maximum competitive at locations like Harvard, Yale, and Dartmouth, which, on average, accept college students with GPAs exceeding 4.

Learn more about GPA here:- brainly.com/question/24276013

#SPJ4

8 0
1 year ago
New Smoke wants to market their cigarettes to young adults, so they decide to create an ad using an attractive celebrity couple.
soldi70 [24.7K]

Answer:

Celebrity Branding

Explanation:

It is an advertising Campaign used by Companies, Brands and other non- profit organizations. Well  known persons and Celebrities are used to promote a product using their fame and social status. It works on the concept that positive images of celebrities endorsing a brand will also make their followers buy the product. It is especially used by beauty and fashion brands. Non-profit organizations also rely on celebrities to attract awareness toward a certain issue as celebrities have mass communication skills and can reach a wider audience.

6 0
3 years ago
) A company determines that its marginal revenue per day is given by R'(t) = 100et , R(0) = 0, where R(t) = the revenue, in doll
Vika [28.1K]

Answer:

$14038

Explanation:

The company has marginal revenue R'(t) = 100e^t. Therefore its revenue R(t) is given as;

R(t) = ∫R'(t)

R(t)= ∫ 100e^t dt =  100e^t + c

R(t) =  100e^t + c

But R(0) = 0, therefore:

R(0) =  100e^0 + c = 0

100e^0 + c = 0

100 + c =0

c = -100

Also the marginal cost per day is given by C'(t) = 140 - 0.3t

C'(t) = 140 - 0.3t

C(t) = ∫C(t) = ∫ (140 - 0.3t) dt = 140t - (0.3/2) t² + C

But C(0) = 0

C(0) = 140 (0) - (0.3/2)(0)² + c = 0

c = 0

C(0) = 140t - (0.3/2) t²

Profit P(t) = R(T) - C(T) , hence the total profit from t = 0 to t = 5 is given as:

P(t) = \int\limits^0_5 {[R'(t)-C'(t)]} \, dt =\int\limits^0_5 {([100e^t-(140-0.3t)]} \, dt=\int\limits^0_5 {100e^t} \, dt  +\int\limits^0_5 {-0.3t} \, dt  +\int\limits^0_5 {-140} \, dt  \\\\=[100e^t]_0^5+[ -140t]_0^5+[-0.3t^2/2]_0^5=[14841.316-100]+[-700]+[-3.75]=14038

The profit is $14038

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