What is the y- value of the vertex of 4c^2+8x-8
1 answer:
Answer:
a =4 b=8 c=-8
y-value of vertex =
ah^2 + bh + c
where h = -b/2a
h= -8/8 =-1
y-value of vertex =
4(-1)^2 + 8*-1 -8
4 -8 -8
y value of vertex = -12
Step-by-step explanation:
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