3 years ago

What is the y- value of the vertex of 4c^2+8x-8

Mathematics

1 answer:

NeX [460]3 years ago

7 0

Answer:

a =4 b=8 c=-8

y-value of vertex =

ah^2 + bh + c

where h = -b/2a

h= -8/8 =-1

y-value of vertex =

4(-1)^2 + 8*-1 -8

4 -8 -8

y value of vertex = -12

Step-by-step explanation:

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