10+ x/6 i believe this is the answer
<span> The least perimeter occurs when rectangle is square.
So you can start by taking square root of area; </span>√32
So each side is √32 and there are 4 sides
Hence least perimeter is 4√32 = 16√2 ≈ 22.627.
Answer:
Step-by-step explanation:
P = 2S + 2L
2S + 2L = P
2S = P - 2L
S =
Refer to the attached diagram for further a visual explanation. As per the given information, segments (AB) and (AD) are congruent. Moreover, segments (AC) and (AE) are also congreunt. One is also given that angles (<BAD) and (<EAC) are congruent. However, in order to prove the triangles (ABC) and (ADE) are congruent (using side-angle-side) congruence theorem, one needs to show that angles (<BAC) and (<DAE) are congruent. An easy way to do so is to write out angles (<BAC) and (<DAE) as the sum of two smaller angles:
<BAC = <BAD + <DAC
<DAE = <DAC + <EAC
Both angles share angle (DAC) in common, since angles (<EAC) and (BAD) are congruent, angles (<BAC) and (<DAE) must also be congruent.
Therefore triangles (ABC) and (ADE) are congruent by side-angle-side, thus sides (BC) and (DE) must also be congruent.
In summary:
AB = AD Given
AC = AE Given
<BAD = <EAC Given
<DAC = <DAC Reflexive
<BAC = <BAD + <DAC Parts-Whole Postulate
<DAE = <EAC + < DAC Parts-Whole Postulate
<BAC = <DAE Transitivity
ABC = ADE Side-Angle-Side
BC = DE Corresponding parts of congruent triangles are congruent