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kotykmax [81]
3 years ago
13

Which cylinder has the greatest volume?

Mathematics
2 answers:
padilas [110]3 years ago
7 0

Answer:

The answer is C. a cylinder with a height of 6 cm and a radius of 12 cm

Step-by-step explanation:

vivado [14]3 years ago
3 0

Answer:

The answer is C. a cylinder with a height of 6 cm and a radius of 12 cm

Step-by-step explanation:

I did it on the assignment

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What’s the length of the wall?
irinina [24]

Answer:

B?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Aaron has a loan of 1250£ He pays simple intrest 0.5% per month for eight months Calculate the total amount of interest Aaron pa
Nimfa-mama [501]
Answer: 50 Pounds

Explanation: First we need to find out how much 0.5% of 1250 is. 0.5% of 1250 is 6.25£. Since that’s per month, and Aaron pays interest for 8 months, we multiply by 8. So 6.25 times 8 is 50.
5 0
2 years ago
Weird question but, whenever you divide by 1/4 or multiply by 4/1, will you always get the same answer.
professor190 [17]

Answer:

yep

Step-by-step explanation:

when you divide a fraction u can use the KCF method which is basically:

(keep) the first fraction the same

(change) the division sign in the middle to a multiplication sign

(flip) the second fraction

basically because you have to flip the 1/4 when you divide it, it'll be the same as a 4/1 anyways

8 0
3 years ago
Eight hundred and five thousends in Decimals
alexira [117]
Eight hundred equals 0.08
Five thousands equals 0.005
7 0
3 years ago
A new fast-food firm predicts that the number of franchises for its products will grow at the rate dn dt = 6 t + 1 where t is th
yaroslaw [1]

Answer:

The answer is "253"

Step-by-step explanation:

In the given- equation there is mistype error so, the correct equation and its solution can be defined as follows:

Given:

\bold{\frac{dn}{dt} = 6\sqrt{t+1}}\\

\to dn= 6\sqrt{t+1} \ \ dt.....(a)\\\\

integrate the above value:

\to \int dn= \int 6\sqrt{t+1} \ \ dt \\\\\to n= \frac{(6\sqrt{t+1} )^{\frac{3}{2}}}{\frac{3}{2}}+c\\\\\to n= \frac{(12\sqrt{t+1} )^{\frac{3}{2}}}{3}+c\\\\

When the value of n=1 then t=0

\to 1= \frac{12(0+1)^{\frac{3}{2}}}{3}+c\\\\ \to 1= \frac{12(1)^{\frac{3}{2}}}{3}+c\\\\\to 1-\frac{12}{3}=c\\\\\to \frac{3-12}{3}=c\\\\\to \frac{-9}{3}=c\\\\\to c=-3\\

so the value of  n is:

\to n= \frac{(12\sqrt{t+1} )^{\frac{3}{2}}}{3}-3\\\\

when we put the value t= 15 then,

\to n= \frac{(12\sqrt{15+1} )^{\frac{3}{2}}}{3}-3\\\\\to n= \frac{(12\sqrt{16} )^{\frac{3}{2}}}{3}-3\\\\\to n= \frac{(12\times 64)}{3}-3\\\\\to n= (4\times 64)-3\\\\\to n= 256-3\\\\\to n= 253

6 0
3 years ago
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