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postnew [5]
2 years ago
5

A student knows the height of a pyramid and the area of its base. What should the student do to find the volume of the pyramid

Mathematics
2 answers:
Varvara68 [4.7K]2 years ago
5 0

Answer:

Multiply the area of the base by the height and divide by 3.

Step-by-step explanation:

V = (1/3)Bh

where B = area of the base, and

h = height

Answer: Multiply the area of the base by the height and divide by 3.

Natali5045456 [20]2 years ago
3 0

Answer:

We khow that the volume of a pyramid is equal the product of the base and the height over 3

So he just needs to multiply them together then divide the result by 3

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Read 2 more answers
Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc
nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

10 word errors.

This means that n = 10

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

E(Y) = np = 10*0.7 = 7

The mean number of errors caught is 7.

What is the mean number of errors missed?

E(X) = np = 10*0.3 = 3

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

6 0
2 years ago
A case of 24 tennis balls weighs 3 pounds. How much would a shipment of 2560 tennis balls weigh? Please write
kolbaska11 [484]

The weight of a shipment of 2560 balls weighs 320 pounds.

<h3>How much would a shipment of 2560 tennis balls weigh?</h3>

We know that 24 tennis balls weigh 3 pounds. Then the weight of a single tennis ball is:

W = (3 lb)/(24 balls) = (1/8) pounds per ball.

To get the weight of 2560 tennis balls, we just need to multiply the number of tennis balls by the weight of a single ball, then we get:

Total weight = 2560*(1/8) pounds per ball = 320 pounds.

The weight of a shipment of 2560 balls weighs 320 pounds.

If you want to learn more about weight:

brainly.com/question/25973294

#SPJ1

8 0
1 year ago
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