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lozanna [386]
3 years ago
11

-4k^2-8k-3 = -3-5k^2

Mathematics
2 answers:
mel-nik [20]3 years ago
8 0
-4k^2-8k-3 = -3-5k^2 \\ \\ -4k^2 - 8k = -5k^2 \\ \\ 4k^2 + 8k - 5k^2 = 0 \\ \\ -k^2 + 8k = 0 \\ \\ 8k - k^2 = 0 \\ \\ k(8 - k) = 0 \\ \\ k = 0,8 \\ \\

The final result is: k = 0, 8.
Mars2501 [29]3 years ago
3 0
--> -4k^2 -8k -3 +3 +5k^2 = 0

k^2 -3k = 0

Apply the quadratic formula

Taking a= 1, b= -3 and c= 0.

Therell be 2 values for k
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a positive number is 7 times another number if 3 is added to both the numbers then one of the new number becomes 5 by 2 times th
Neko [114]

Answer:

7 and 1

Step-by-step explanation:

Let the numbers be a and b.

<u>A positive number is 7 times another number:</u>

  • a = 7b

<u>If 3 is added to both the numbers then one of the new number becomes 5 by 2 times the other new number:</u>

  • a+3 = 5/2 × (b +3)

<u>To solve this we substitute </u><u>a</u><u> with </u><u>7b</u><u> in the second equation:</u>

  • 7b + 3 = 5/2 × (b +3)               ⇒ multiplying both sides by 2
  • 14b + 6 = 5b + 15                    ⇒ collecting like terms
  • 14b - 5b = 15 - 6
  • 9b = 9
  • b = 1                                        ⇒ solved for b

<u>Then, finding a:</u>

  • a= 7b
  • a=7*1
  • a= 7                                        ⇒ solved for a

<u>So the numbers are</u> 7 and 1

3 0
3 years ago
8. It took Sharon 85 minutes to wash three cars. She spent x minutes on each car and 10 minutes
Yuliya22 [10]

Answer:

c. 25 minutes

Step-by-step explanation:

3x + 10 = 85

3x = 85 - 10

3x = 75

x = 25

8 0
3 years ago
81/15 + -14/5 plz it is for a test
Natali [406]

Answer:

13/5 and/or 2.6

Step-by-step explanation:

6 0
3 years ago
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Multiplying a number by 4/5 then dividing by 2/5 is the same as multiplying what number?
prisoha [69]
Multiplying a number by 4/5 and then dividing by 2/5 is the same as multiplying by 2


5 0
3 years ago
What are the solutions of the quadratic equation? 4x^2+34x+60=0
insens350 [35]

Answer:

Option 3) -6,-5/2

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

4x^{2} +34x+60=0  

so

a=4\\b=34\\c=60

substitute in the formula

x=\frac{-34(+/-)\sqrt{34^{2}-4(4)(60)}} {2(4)}

x=\frac{-34(+/-)\sqrt{196}} {8}

x=\frac{-34(+/-)14} {8}

x_1=\frac{-34(+)14} {8}=-\frac{20}{8}=-\frac{5}{2}

x_2=\frac{-34(-)14} {8}=-6

6 0
3 years ago
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