Question

-4k^2-8k-3 = -3-5k^2

Answer 1

$-4k^2-8k-3 = -3-5k^2 \\ \\ -4k^2 - 8k = -5k^2 \\ \\ 4k^2 + 8k - 5k^2 = 0 \\ \\ -k^2 + 8k = 0 \\ \\ 8k - k^2 = 0 \\ \\ k(8 - k) = 0 \\ \\ k = 0,8$

The final result is: k = 0, 8.

Answer 2

--> -4k^2 -8k -3 +3 +5k^2 = 0

k^2 -3k = 0

Apply the quadratic formula

Taking a= 1, b= -3 and c= 0.

Therell be 2 values for k