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Lelu [443]
3 years ago
12

The dimensions of a parking lot are measured in feet. What units will the area be measured in?

Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

D) feet²

Step-by-step explanation:

Area = side × side

= feet × feet

= feet²

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Please help me with this question. I will mark you brainliest. ​
solong [7]

<u>Answer:</u>

<em>Option D : $153</em>

<u>This is how I got that:</u>

9:30 AM to 1:15 PM = 3 hours and 45 minutes

The first hour charges $15 and for the remaining 2 hours and 45 minutes

Mr. Anand is charged 36$. Remember it says that each additional hour <em>or part thereof, </em>so the 2 hours and 45 minutes is considered 3 hours.

So our total for one paddle boat is <u>$51 </u>

<u />

But Mr. Anand hired <em>three</em> boats so we simply times 51 by 3 and get our solution to the problem:

<u>Mr. Anand must pay $153 or Option D</u>

<u></u>

<em>~That's All Folks~</em>

<em>-Siascon</em>

4 0
3 years ago
How is the graph of y=3(x+1)^2 related to its parent function y=x^2
creativ13 [48]
The parent function is y = x^2

There is a compression of 3:

y = 3x^2

There is a shift by 1 unit to the left:

y = 3(x + 1)^2
3 0
3 years ago
Read 2 more answers
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
7. What is the perimeter around this figure in feet?
Hoochie [10]

Answer:

20.667

Step-by-step explanation:

7 0
3 years ago
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Given an initial polynomial of x^2 + 2x, which polynomial needs to be added to it
Flauer [41]

Answer:

I wish i was in high school but 2 more years left for me so sorry i cant help :(

Step-by-step explanation:

:(

4 0
3 years ago
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