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solmaris [256]
3 years ago
10

Use technology to create an appropriate model of the data.

Mathematics
2 answers:
Citrus2011 [14]3 years ago
7 0

Answer:

f(x) = 3x - 3

Step-by-step explanation:

Plug into TI-83/84 calculator.

Hit STAT

Hit EDIT

X-Values go in for L1

Y-Values go in for L2

Hit STAT

Scroll over to CALC

Hit #4 for LinReg (Finds line of best fit)

Enter all the way through

A is your slope

B is your y-intercept

Lilit [14]3 years ago
4 0

Answer:

f(x)=3x-3  

Step-by-step explanation:

Data : (-2,-9), (0,-3), (1,0), (3,6), (5,12)

Using technology , Plot the points on the calculator .

(Refer the attached figure)

Or

First calculate the slope of given points

m = \frac{y_2-y_1}{x_2-x_1}   ---A

(x_1,y_1)=(-2,-9)

(x_2,y_2)=(0,-3)

Substitute values in A

m = \frac{-3-(-9)}{0-(-2)}

m = \frac{-3+9}{2}

m = \frac{6}{2}

m = 3

(x_1,y_1)=(1,0)

(x_2,y_2)=(3,6)

Substitute values in A

m = \frac{6-0}{3-1}

m = \frac{6}{2}

m = 3

Since the slopes are same .

So, the the given data is a linear function.

Now to obtain the equation for data we will use two point slope form.

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)   ---B

(x_1,y_1)=(-2,-9)

(x_2,y_2)=(0,-3)

Substitute values in B

y+9= \frac{-3-(-9)}{0-(-2)}(x+2)  

y+9= \frac{6}{2}(x+2)  

y+9=3(x+2)  

y+9=3x+6  

y=3x+6-9  

y=3x-3  

So, f(x)=y=3x-3  

Thus Option B is true .

Hence the required equation is  f(x)=3x-3  

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3 years ago
3
saveliy_v [14]

Answer:

sorry you can send me picture of work

Step-by-step explanation:

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slega [8]

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Step-by-step explanation:

5 0
2 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

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3 years ago
What are the center and radius of the circle defined by the equation x^2 y^2-6x 4y 4=0?
Kazeer [188]
Please rewrite this equation of the circle correct with signs of minus or plus 
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