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Alexeev081 [22]
3 years ago
13

.

Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0
I think it would be 4 hours sorry if I'm wrong
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More Literal Expressions, please include the way you worked out.
Artyom0805 [142]

A=h/2(a+b) solver for h

2A=h(a+b)

2A/(a+b)=h   (Solution)

4 0
4 years ago
SV is angle bisector of
DochEvi [55]

Answer:

<h3>Sv is angle bisector of rst.</h3>
8 0
2 years ago
Help answer please!!
12345 [234]

Answer:

h = 19.7 ft.

Step-by-step explanation:

Use the Pythagoras Theorem

(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\\\(20)^2=(3.5)^2+(h)^2\\400=12.25+h^2\\400-12.25=h^2\\387.75=h^2\\

Now we take square root on both sides,

\sqrt{387.75} =\sqrt{h^2}\\19.69=h\\h=19.7\ ft\\

so the value of h equals 19.7 ft.

6 0
3 years ago
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

4 0
3 years ago
A football team lost 5 yards on each of 3 plays. Explain how you could use a number line to find the team's change in field posi
taurus [48]

Answer:

Step-by-step explanation:

5- 10- 15-

3 0
3 years ago
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